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taylorswift08
Full Member
Posts: 11
Joined: Mon Mar 20, 2023 8:36 am

Chemistry

Can somoone plesa see this exercise?

For the reaction PCl3+Cl2-PCl5, at a certain temperature k=4. Calculate the speed of this reaction when the concentration of PCl3 is 3 mol/l and the concentration of Cl2 is 2 mol/l. What is the speed of this reaction at this temperature when there are 1.5 mol of Cl2 left in the container?
ChenBeier
Distinguished Member
Posts: 1313
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

Re: Chemistry

K = cPCl5/(cPCl3*cCl2)

4 = x/((3-x)*(2-x)) solve for x.

The other reaction is
If 1,5 mol/ l Cl2 is left then 0,5 mol/l has reacted. What means the same amount of PCl3 has reacted and also the same amount PCl5 was obtained.

K= 0,5/((3-0,5)*(2-0,5))
taylorswift08
Full Member
Posts: 11
Joined: Mon Mar 20, 2023 8:36 am

Re: Chemistry

Okat then a) 24 mol/l*s
b) 15 mol/l*s is this right?
ChenBeier
Distinguished Member
Posts: 1313
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

Re: Chemistry

Yes I would think so