What a big deal
4 C10H10BrNO3 + 47 O2 => 40 CO2+ 4 HBr+ 4 NO2+ 18 H2O
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- Thu Feb 22, 2024 1:40 pm
- Forum: Chemistry forum
- Topic: Combustion reaction of the alkaloid matemone C10H10NO3Br
- Replies: 2
- Views: 332
- Wed Feb 21, 2024 12:00 am
- Forum: Chemistry forum
- Topic: Solution Chloroplatinic acid?
- Replies: 3
- Views: 1330
Re: Solution Chloroplatinic acid?
Sorry it is nonsense what you say. Even Chloroplatinic acid is used as an catalyst it is inorganic and not organic. If you don't know the difference then your expertise is poor.
By the way we dont like comercial Postings.
By the way we dont like comercial Postings.
- Mon Feb 19, 2024 11:34 pm
- Forum: Chemistry forum
- Topic: Solution Chloroplatinic acid?
- Replies: 3
- Views: 1330
Re: Solution Chloroplatinic acid?
Convert mM in mg/l, use m = n* M
The density is not necessary, because its a solid material. You can only dissolve a powder in water. No volume.
Then calculate it for 10 ml.
The density is not necessary, because its a solid material. You can only dissolve a powder in water. No volume.
Then calculate it for 10 ml.
- Mon Feb 19, 2024 3:37 am
- Forum: Chemistry forum
- Topic: its right or not ?
- Replies: 1
- Views: 284
Re: its right or not ?
Its ok , but there are no half molecules even mathematicaly correct
Times two
2 C2H6 + 7 O2 => 4 CO2 + 6 H2O
Times two
2 C2H6 + 7 O2 => 4 CO2 + 6 H2O
- Sat Feb 17, 2024 10:21 am
- Forum: Chemistry forum
- Topic: Calcium Hydroxycitrate vs Hydroxycitric Acid + Alpha Lipoic Acid
- Replies: 4
- Views: 1377
Re: Calcium Hydroxycitrate vs Hydroxycitric Acid + Alpha Lipoic Acid
Yes of course it will work. But you have to know which one you will make. Citric acid has 3 Protons, these can be exchanged step by step by a metal, here Calcium, which is bivalent. So there will be CaHCit., Ca(H2Cit)2 and Ca3(Cit)2.
- Sat Feb 17, 2024 9:24 am
- Forum: Chemistry forum
- Topic: Calcium Hydroxycitrate vs Hydroxycitric Acid + Alpha Lipoic Acid
- Replies: 4
- Views: 1377
Re: Calcium Hydroxycitrate vs Hydroxycitric Acid + Alpha Lipoic Acid
We can not give answers for pharmaceutical purpose.
(Hydroxy)-citric acid can be neutralized with Calcium carbonate to the citrate.
(Hydroxy)-citric acid can be neutralized with Calcium carbonate to the citrate.
- Wed Feb 14, 2024 3:08 pm
- Forum: Chemistry forum
- Topic: Titration of mixture of KOH and K2CO3
- Replies: 11
- Views: 1270
Re: Titration of mixture of KOH and K2CO3
You cannot determine different Isotops of one element by titration. If you check for potassium then you will get all Isotopes together. The Isotopes are different by the amount of neutrons in the atom, this is not possible to figure out by chemical analysis. The chemical behaviour is driven by the a...
- Tue Feb 13, 2024 4:08 am
- Forum: Chemistry forum
- Topic: Titration of mixture of KOH and K2CO3
- Replies: 11
- Views: 1270
Re: Titration of mixture of KOH and K2CO3
In this case convert all to KCl. pH 7.
Probably the determination of molarity of HCl is also wrong. If it was only the half instead 0.0098 M only 0.0049 M then it would more or less fit.
Probably the determination of molarity of HCl is also wrong. If it was only the half instead 0.0098 M only 0.0049 M then it would more or less fit.
- Tue Feb 13, 2024 3:46 am
- Forum: Chemistry forum
- Topic: Titration of mixture of KOH and K2CO3
- Replies: 11
- Views: 1270
Re: Titration of mixture of KOH and K2CO3
The solution p Value is sum of KOH and 1/2 K2CO3 or KHCO3 ( ml HCl consumed Phenolphthalein) m value is sum of KOH and K2CO3 ( ml HCl consumed Methylorange) n (KOH) = 2 p - m = 2*(KOH + 1/2 K2CO3) - (KOH + K2CO3) = KOH n ( K2CO3) = 2*(m-p) = 2*(KOH + K2CO3 - (KOH + 1/2 K2CO3)) = K2CO3 n KOH = 2 * 26...
- Sun Feb 11, 2024 11:24 pm
- Forum: Chemistry forum
- Topic: Titration of mixture of KOH and K2CO3
- Replies: 11
- Views: 1270
Re: Titration of mixture of KOH and K2CO3
Values for KOH and K2CO3 have to be exchangend.
See here an example with sodiumhydroxide and Carbonate
https://www.linkedin.com/pulse/analytic ... oda-kartal
See here an example with sodiumhydroxide and Carbonate
https://www.linkedin.com/pulse/analytic ... oda-kartal
- Sun Feb 11, 2024 3:56 am
- Forum: Chemistry forum
- Topic: Chloroauric acid
- Replies: 6
- Views: 606
Re: Chloroauric acid
You need about 355 ml solvent for the 0.7 g.
But read how to make it
What is aqua Regina it is 3 part HCl and one part HNO3 .
https://en.m.wikipedia.org/wiki/Chloroauric_acid
You have to do boiling until all HNO3 is evaporated as NO2, later dissolve the product again in conc. HCl to get 355 ml
But read how to make it
What is aqua Regina it is 3 part HCl and one part HNO3 .
https://en.m.wikipedia.org/wiki/Chloroauric_acid
You have to do boiling until all HNO3 is evaporated as NO2, later dissolve the product again in conc. HCl to get 355 ml
- Sun Feb 11, 2024 3:40 am
- Forum: Chemistry forum
- Topic: Chloroauric acid
- Replies: 6
- Views: 606
Re: Chloroauric acid
I thing to figure out what is aqua Regina and the calculati8n you have to do by yourself.
Calculate the moles of Gold you have then covert this to the volume of the acid to get 0,01 M
Calculate the moles of Gold you have then covert this to the volume of the acid to get 0,01 M
- Sun Feb 11, 2024 2:52 am
- Forum: Chemistry forum
- Topic: Chloroauric acid
- Replies: 6
- Views: 606
Re: Chloroauric acid
Dissolve in aqua Regina.
- Sat Feb 10, 2024 1:21 pm
- Forum: Chemistry forum
- Topic: Titration of mixture of KOH and K2CO3
- Replies: 11
- Views: 1270
Re: Titration of mixture of KOH and K2CO3
Yes something doesn't fit.
The titration values are wrong or the method to get molarity of HCl.
The titration values are wrong or the method to get molarity of HCl.
- Sat Feb 10, 2024 8:35 am
- Forum: Chemistry forum
- Topic: Titration of mixture of KOH and K2CO3
- Replies: 11
- Views: 1270
Re: Titration of mixture of KOH and K2CO3
It was asked for potassium not for potassium carbonate or hydroxide.
The moles for K2CO3 are wrong
K2CO3 + 2 HCl => 2 KCl + H2O + CO2
For 1 K2CO3 2 HCl needed or 1 HCl correspond to 1/2 K2CO3
n (K2CO3) =0,0261 *0,09817/2 = 0,001281 mol
The moles for K2CO3 are wrong
K2CO3 + 2 HCl => 2 KCl + H2O + CO2
For 1 K2CO3 2 HCl needed or 1 HCl correspond to 1/2 K2CO3
n (K2CO3) =0,0261 *0,09817/2 = 0,001281 mol