Chemistry Forum

Sorry we dont discuss for self made pharmacy.

What is the topic, for what you need the Amino acids.

No commercials here.

Compare the theoretical consumption with the real one.
Calculate the moles you used and the moles of the NaOH react.

Carbonate will be destroyed by acid to CO2 and water. So this can be used. Hydroxid get neutralization to water. All others have not effekt.

Potassium hydrogen carbonate, potassium carbonate and potassium hydroxide can be used.

Palladium(II) chloride is prepared by dissolving palladium metal in aqua regia or hydrochloric acid in the presence of chlorine. Alternatively, it may be prepared by heating palladium sponge metal with chlorine gas at 500 °C.

Here we go Propadiene a = 8,23 l^2* bar/ mol^2, b= 0,0747 l/mol Methylacetylene is Propyne a = 8,4 l^2*bar/mol^2, b= 0,0744 l/mol https://www.google.com/url?q=https://drjvazque.files.wordpress.com/2017/08/propiedades-criticas.pdf&sa=U&ved=2ahUKEwjks6Gn-L7yAhXFxoUKHWKhAJQQFnoECAgQAQ&usg=A...

I am really sorry to hear that a fire is close to your place. This planet is dying.

Your results are correct.

DEFINITION here:


https://energyhq.com/2017/04/upstream-m ... ifference/

All nonsense

1 J = Nm =1 Ws = 1 VAs

3,7 Watt is power not not work, the time is missing
13320 J is 13320 VAs = 3,7 VAh
The Charge is 7,2 * 10^-3 Ah, if the voltage is known then the work can be calculated.

Consider the vessel is 8 dm^3. In this is filled 2,5 dm^3 CH4 and 4.5 dm^3 O2 . In total 7 dm^3. 1 dm^3 is missing so we have some expansion. of the gases. The two pressures are also different. p1V1 + p2V2 = ptotal* Vvessel pV ~ n. RT is constant. From this you have to get total pressure and the par...

The candidate has 99 points. If you reach 100 points you get a light cookie.

But to achieve this calculation it goes faster 2,666/5 = 0,5332
And 2,333/5 = 0,4666

Because V~ n.

What is your result?

pV = nRT

P, R and T are constant so n~V

V(CH4) + V(C2H6) = 5 dm^3

2V(O2(CH4)) + 3,5V(O2(C2H6)) = 13,5 dm^2

Substitute Ethane by 5dm^3 - V(CH4) = V(C2H6)

x + y = 5
2 x + 3,5 y =13,5