I dont think so, because the equilibrium will be on left side. Two precipitate on left and on right side only one.
Check the solubility constant from each product.
Also hydrogencarbonate is slightly acidic. Calcium hydroxide strong alcaline, this will neutralise.
Search found 1565 matches
- Tue Apr 09, 2024 7:43 am
- Forum: Chemistry forum
- Topic: Mg(OH)2 + CaCO3 + H2O = Mg(HCO3)2 + Ca(OH)2
- Replies: 3
- Views: 153
- Tue Apr 09, 2024 4:56 am
- Forum: Chemistry forum
- Topic: Mg(OH)2 + CaCO3 + H2O = Mg(HCO3)2 + Ca(OH)2
- Replies: 3
- Views: 153
Re: Mg(OH)2 + CaCO3 + H2O = Mg(HCO3)2 + Ca(OH)2
First the equation is not balanced, second why do you think this should happen. To get hydrogencarbonate excess of carbondioxide is needed.
This works without and with the calcium already.
Can be find in stalactite caves.
This works without and with the calcium already.
Can be find in stalactite caves.
- Mon Apr 08, 2024 10:59 pm
- Forum: Chemistry forum
- Topic: Exercise on pH
- Replies: 3
- Views: 643
Re: Exercise on pH
That is what I said above. Why repetation.
- Mon Apr 08, 2024 3:07 am
- Forum: Chemistry forum
- Topic: Question on Molarity and Solubility
- Replies: 3
- Views: 248
Re: Question on Molarity and Solubility
Read the principles of Le Chatelier. Here you make from two reactants one product. So it means decrease Volume or increase pressure will give more product .Figure out is the reaction exothermic or endothermic. Means consume or release heat. If it consumes rise temperature, in other case decrease tem...
- Sun Apr 07, 2024 11:38 pm
- Forum: Chemistry forum
- Topic: I need help with some questions and types of problems
- Replies: 1
- Views: 126
Re: I need help with some questions and types of problems
1. Soap is made of amphipathic particles, the hydrophil part dissolves in water the hydrophob part in fat or oil. The soap molecules develop micelles. A dirt particle is fatty, so the particle will be surounded from the soap molecules, by stickig the hydrophob part in. The hydrophil part will be in ...
- Fri Apr 05, 2024 1:04 am
- Forum: Chemistry forum
- Topic: Understanding the Equilibrium Constant Expression
- Replies: 1
- Views: 109
Re: Understanding the Equilibrium Constant Expression
Law of mass action
K = C^c*D^d/(A^a*B^b)
K = constant, so changes of one component will affect all others.
https://www.chemistrylearner.com/law-of ... ction.html
K = C^c*D^d/(A^a*B^b)
K = constant, so changes of one component will affect all others.
https://www.chemistrylearner.com/law-of ... ction.html
- Tue Apr 02, 2024 11:25 pm
- Forum: Chemistry forum
- Topic: How to make Sodium hydroxymethanesulfonate
- Replies: 10
- Views: 414
Re: How to make Sodium hydroxymethanesulfonate
No it doesn't effect.
- Tue Apr 02, 2024 7:53 am
- Forum: Chemistry forum
- Topic: How to make Sodium hydroxymethanesulfonate
- Replies: 10
- Views: 414
- Thu Mar 28, 2024 4:01 am
- Forum: Chemistry forum
- Topic: Redox reactions
- Replies: 5
- Views: 326
Re: Redox reactions
Because in the logarithmen I used cox/cRed. Not the opposit. Log cox/ cred = - log cred/cox log/cI2/c^2I- = - logc^2I-/ cI2 https://en.m.wikipedia.org/wiki/Nernst_equation You are right it should be a minus like in the Literature but also the reduced form as numerator and the oxidised form as denomi...
- Thu Mar 28, 2024 12:50 am
- Forum: Chemistry forum
- Topic: Redox reactions
- Replies: 5
- Views: 326
Re: Redox reactions
Redox Potentials are measured to hydrogen and considered as oxidation.
I-/I2 is positiv. 0,535 V
NO2-/ NO3- is also positiv 0,94 V
Elements are put in by definition as 1 .
I-/I2 is positiv. 0,535 V
NO2-/ NO3- is also positiv 0,94 V
Elements are put in by definition as 1 .
- Wed Mar 27, 2024 11:07 pm
- Forum: Chemistry forum
- Topic: Acid sulfuric
- Replies: 1
- Views: 191
Re: Acid sulfuric
The question is what you want to do with this water later on. The sulfuric is an technical one and contain impurities, which can disturb further reactions. Only to lower pH it will work, but 95% is to strong. I dont think you can react pH 5 by using drops, it will go down to 1 or 2. What is the volu...
- Wed Mar 27, 2024 3:40 pm
- Forum: Chemistry forum
- Topic: Redox reactions
- Replies: 5
- Views: 326
Re: Redox reactions
We have two equations HNO2 + H2O => HNO3 + 2 H+ + 2e- 2 I- => I2 + 2 e- Nernst equation E1 = E0 + 0,059/2*log ( cHNO3 * c^2 H+ /c HNO2) E2 = E0 + 0,059/2 *log (cI2/c^2 I-) First equation cHNO3 = cHNO2 E1 = 0,94 +0,059/2 * log(c^2H+) pH = -log cH+ E1 = 0,94 - 0,059*pH Second equation E2 = 0,535 + 0,0...
- Wed Mar 27, 2024 5:06 am
- Forum: Chemistry forum
- Topic: How to make Sodium hydroxymethanesulfonate
- Replies: 10
- Views: 414
Re: How to make Sodium hydroxymethanesulfonate
Read again the Article, you get both.
- Tue Mar 26, 2024 10:58 pm
- Forum: Chemistry forum
- Topic: Complex Formation Equilibria
- Replies: 1
- Views: 204
Re: Complex Formation Equilibria
You need the complex building constant for CeY-.
Ce 3+ + Y 4- => CeY-
K = CeY-/(Ce 3+ *Y 4-)
pH dependency
Ce 3+ + Y 4- => CeY-
K = CeY-/(Ce 3+ *Y 4-)
pH dependency
- Tue Mar 26, 2024 8:45 am
- Forum: Chemistry forum
- Topic: K3RhCl6
- Replies: 3
- Views: 207
Re: K3RhCl6
I would react the salt first with sulfuric acid, to get rid of the Chloride.
The remaining Rhodiumsulfate can be electrolysed. Cathode what ever you like. Anode carbon preferred.
The remaining Rhodiumsulfate can be electrolysed. Cathode what ever you like. Anode carbon preferred.