Chemistry Forum

Fill burette with 0.5 m HCl. The water is add that the Erlenmeyerflask can be shaked easier and to see the liquid. 10 ml NaOH will be not seen, the Level is to low. ((VHCl *cHCl/VNaOH)* MNaOH/Rho)*100% = c% Is VHCL = Volume of HCL yes cHCL = concentration of HCL yes VNaOH = Volume of Sodium hydroxid...

Equippment Erlenmeyerflask 250ml and a Burette 25 ml, Pipette 10 ml HCl 0,5 n Phenolphthaleine indicator Add 10 ml NaOH into the erlenmeyer flask, add some drops indicator and add 20 ml water. Fill the burette with 0,5 n HCl Titration by shaking the Erlenmeyer flask until the solution turn from pink...

The final results are ok, I am wondering where the 2 H+ + 2e- comming from. Especially there is no acid in 1. and 2. Fe 2+ => Fe 3+ + e- Oxidation Ce 4+ +e - => Ce 3+ Reduction Fe 2+ + Ce 4+ => Fe 3+ + Ce 3+ Addition Sulfate is spectator ion For completion multiply by 2 and add SO4 2- 2 FeSO4 + 2 Ce...

If you wish to attach one or more files enter the details below. You may also attach files by dragging and dropping them in the message box. Maximum filesize per attachment: 1 MiB. You have to have jpg or PDF. For redox reaction use the redox pair law a) S2O3 2- / S4O6 2- and I2/I- 2 S2O3 2- => S4O6...

The basic is the law of faraday

m = I * t * c
c = electrochemical equivalent =M/ (z *F)

m= mass, I = current, t= time, M = molar mass, z = amount of transferred electrons, F = Faraday constant 96485 As,

Nothing happen.

pH = pKs - log((cHCO3-)/(cCO3 2-))

I think the amount is driven from the limiting agent. Ca 2+ is limited ion. Everything what is above the soloubilty will precipitate. Its about 2.38 g.

Check what is limiting agent.

The absorbtion of 823,7 kJ/ mol for water is correct. But how you get the other values. What is the 7nitial temperature of iron?

Who said that. In first it was told your result is wrong. So take the equation half, the Addition of educt is one enthalpy value. The product also have value, what has subtracted vom educt value, it gives negative value. The cobaltoxide reaction. First CoO is formed with negativ value, from there Co...

Sounds ok

The first one is -59.65 kJ/ mol educt- product.

The second one 3*(-120,6 kJ/mol) + (-632,4 kJ/mol) = -994,2 kJ/ mol

It is not asked. You can calculate the heat what was absorbed by the water.
But you could calculate the Initial temperature of iron.

You changed the question after I answered. The answer refered to the first 2 questions. I meant 1 and to 2 are correct.

Then only 3a is correct

And 4 b

Both are correct.