Chemistry Forum

Hi everyone, i need your help again. I have this exercise: "In a closed reactor of 8.00 dm ^ 3, thermostated at a certain temperature, 2.50 dm ^ 3 of methane, CH4, measured at the pressure of 1.45 * 10 ^ 5 Pa, are mixed with 4.50 dm ^ 3 of oxygen, measured at 2.70 * 10 ^ 5 Pa and at the same te...

thanks for the help, I asked for help on an Italian forum but I have not received an answer. It is the first time that I have encountered an exercise of this kind, and among the exercises carried out by my professor there was none of the kind.

here is my development :
x+y=5 y=2,33
2x+7/2y=13,5 x=2,66
n(tot)=V/Vm= 5 L/22,414 L= 0,223
n(CH4)=2,66/22,414=0,1189 mol; X(CH4)=n(CH4)/n(tot)=0,1189/0,223=0,533
n(C2H6)=2,33/22,414=0,1041 mol; X(C2H6)=n(C2H6)/n(tot)=0,1041/0,223=0,467
it's correct?

thank you very much, really. I had guessed the proportions but I hadn't put them into a system.

Hello everyone, would you help me understand how to solve the following exercise? "For complete combustion of 5.00 dm ^ 3 of a mixture of methane, CH4, and ethane, C2H6, 13.50 dm ^ 3 of oxygen are needed, measured at the same conditions of temperature and pressure: CH4 (g) + 2O2 (g) -> CO2 (g) ...