Chemistry Forum

Thanks for your correct answers to questions (a), (b), (c) and(d). My Computation work for answers to question (e) and (f). My answer to (e) P_{CCl_4}=0.981 \times 100 mm=98.1 mm, P_{CCl_4}= Vapor pressure of solution My answer to (f) \Delta T_{bp}=K_{bp}\times m; m= \frac{\Delta T_{bp}}{K_b}=\frac{...

A solution is prepared by 10 g of solid para-dichlorobenzene (C6H4Cl2) in enough carbon tetrachloride to make a total of 350 mL of solution. The density of the resulting solution is 1.60 g/mL . (a) Compute the molarity of the solution. (b) Compute the weight % para-dichlorobenzene of the solution. (...

I think computed boiling point of the solution 81.255℃ is correct.

What is the value of second equilibrium constant for HOOC-COOH? Is it 5.42e-5?

We know that 1.286 g of the compound are dissolved in 25 g benzene, and therefore in 1000 g of benzene, there are 1.286 \times \frac{1000}{25}=51.44 g, \Delta T_{fp} = 5.50^\circ -3.27^\circ =2.23^\circ C; \Delta T_{fp} = K_{fp}\cdot m; m=\frac{\Delta T_{fp}}{K_{fp}}=\frac{2.23}{5.12}=0.436 m; \frac...

I am wrong. I modified wrongly the original question given by authors. Now I corrected the question and answer. You may check it now.

After a sample of compound X weighing 1.286 g was dissolved in 25 g of C6H6, the freezing point of the resulting solution was found to be 3.27℃. What is the molecular weight of compound X? What is the name of solute compound? What is the boiling point of the solution? My answer: Molecular weight of ...

pH of oxalic acid is given 5.4e-2 in table of equilibrium constants for acids and bases in aqueous solution. But, on other chemistry website , it is stated as '' The constant acid dissociation of oxalic acid is 5.60 between 10⁻² and 5.42 between 10⁻⁵. As oxalic acid is a polyprotic acid, there are t...

Thanks for your guidance. After doing some chemistry work i got the correct answer. 20 ppb =0.2e-7 l = 0.2e-7 kg = 0.2e-7 × 10³ g=200.0 e-7 g ~ 1.0 e-7 M

So, my answer is also correct which is 1.09e-6 M/l. This solution is also like a water

But mol/Kg and mol/liter are inconsistent units. How did you make unit conversion?

If any water reserve has lead concentration of 20 ppb, how is that = 1 × 10⁻⁷ M Pb²⁺.

My attempt: 20 ppb=x L/1 L solution → x= 20 × 10⁻⁹ L

Now density of

Pb²⁺=11.34 g/cm³ → 20ppb =1.09 × 10⁻⁶ M Pb

Where i am wrong?

Thanks for your correct answer.

Is the balanced chemical equation for the above chemical reaction correct?

3 HF + 2 HNO3 + 3 CH3COOH + 6Al → 2 Al2O3 + AlF3 + AlC6H9O6 + 4 H2 + N2

What is the equation and type of this chemical reaction?