Chemistry Forum

Number 1 is correct
Number 2 is like in math 1/2 + 1/3
Number 3 is similar Number 2
Number 4 HSO4 as neutral not existing. Otherwise H2SO4 has to be used.

You will get coppersulfide CuS
The formula of coppernitrate is wrong.

You bake lead oxide not lead metal, fumes are less, but a good hood with ventilation would be solve that Problem.

So long you live, you will Inhalt oxygen and breath out CO2. Aber you die it will bestopped.

You add hydroxide, Filtration the precipitate and then bake it.

Yes you can add sodium carbonate and sodium hydroxide

Take some iron nails and dissolve them in sulfuric acid. Or use iron nail to reduce iron-III

Ghostwriting has not be used in scientific publications. The work in science hast to be published from the people who did the work. This goes down to the work on school. The homework should done from the students not from a Ghostwriter.

Who told this. Chlorine doent remove anything. It kills bugs and virus, but the dead animals still existing. There is no removement. For that you need filtration over active carbon.

Water (pH neutral) works like acid and neutralize a metal oxid to Hydroxide what gives alkaline solution.

And nonmetal oxide with water gives acid , because in this case water is a base.

No your answer is correct Ratio is 1 K2Cr2O7 to 6 Na2C2O4 We have 50 ml 0.3 M Na2C2O4 what is 15 mmol So we need 1/6 of 15 mmol = 2,5 mmol K2Cr2O7 The molarity is 0,2 M so we need 2,5mmol/0,2 mmol/ml = 12,5 ml Your question we have 6×0.2M× V1=2×0.3M × 50 ml Where does the 2 comes from, it is the sam...

Thiosulfat will be go to sulfate S2O3 2- + 10 OH- => 2 SO4 2- + 5 H2O + 8 e- Ozon will be to normal oxygen O3 + H2O + 2 e- => O2 + 2 OH- Second equation multiply by 4 4 O3 + 4 H2O + 8 e- => 4 O2 + 8 OH- Addition S2O3 2- + 10 OH- +4 O3 + 4 H2O + 8 e- => 2 SO4 2- + 5 H2O + 8 e- + 4 O2 + 8 OH- Simplef...

I dont know for what the citrate is for.

The reaction is Y(NO3)3 + 3 NaOH => Y(OH)3 + 3 NaNO3

Correct answers

What do you mean with Oxidation temperature. Boron is already oxidised
to B 3+ .