Chemistry Forum

Iron powder rusts at a much faster rate than an iron nail.

Is this statement true?
If yes, what is your explanation?
If no, what is your explanation?

(A)The rate law for a certain gaseous reaction is Rate=k[A][C]. If the pressure in the reaction vessel is halved and all other conditions remains the same, the rate of the reaction is decreased by a factor of (a) 1 (b) 2 (c) 0.5 (d) 0.1 My answer is (a). Is this answer correct? if yes, why it is cor...

Very detailed answer, Thank you.

Boiling point and melting point: The minor difference between the electronegativities of hydrogen and carbon means that the bond between both of them is only weakly polar. If two alkanes having the same molecular weights are there then the highly branched one will have the lower boiling point. The m...

Your answer looks correct. Thank you.

I think my answer to a) is wrong. Your answer 75 ml of K2Cr2O7 is correct. But I have another answer as well 2) Using this formula v.f.1 × M1 × volume1= v.f.2× M2 × volume2 Plugging in the values available with us into this formula, we have 6×0.2M× V1=2×0.3M × 50 ml = 25 ml of Potassium Dichromate W...

Answer to a) Redox equation is K2Cr2O7 + 6Na2C2O4 + 14H^+ → 12CO2 + 2Cr + 2K^+ + 12Na^+ + 7H2O From the aforesaid redox equation, we can say that to oxidize 6 moles of Na2C2O4 (Sodium Oxalate), one mole of Potassium Dichromate (K2Cr2O7) is required. So, for 0.3M Sodium Oxalate 0.05 M Potassium Dich...

My attempt to answer all these questions: a) 75 mL of 0.2M K2Cr2O7 is required to oxidize 50 mL of 03M Na2C2O4 in acidic medium. b) 0.4 mole of KMnO4 is required to react completely with 1 mole of K2C2O4 in acidic medium. c) 120 mL of 0.1M KMnO4 is required to oxidize 100 mL of 0.3M FeC2O4 in acidic...

a) What volume of 0.2 M K2Cr2O7 is required to oxidize 50 ml of 0.3 M Na2C2O4 in acidic medium? b)How many moles of KMnO4 will be required to react completely with 1 mole of K2C2O4 in acidic medium? c) What volume of 0.1 M KMnO4 is required to oxidize 100 ml of 0.3M FeC2O4 (Ferrous Oxalate) in acidi...

Yes, your answer is correct.

My answer to the following question is 0.02 N But the answer given is 0.2N. Where I am wrong? Question :Calculate the normality of NaOH solution formed by dissolving 0.2 gm NaOH to make 250 ml solution. Solution: Normality (N) = \frac{number of Gram Equivalent of solute}{Volume of Solution in litre}...

0.005 g of a protective colloid is required to prevent precipitation of 1 ml of gold sol on addition of 10 ml of 10% NaCl. The gold number is (A) 0.5 (B) 5 (C) 50 (D) 500 My answer is 0.05 milligrams. Is that correct? My computed answer is not appearing four multiple choices. So i think this questio...

Why 1) d is incorrect?
If it is incorrect, then b is correct. Isn't it?

Solution: The titration calculations for NaOH: For 20 ml acid solution: 15 ml 0.12 mol NaOH required So, the number of base equivalents = 0.12 × 0.015 = 1.8 × 10⁻³ equivalent So, in 20 ml of acidic solution 1.80 x 10⁻³ equivalent of acids Therefore molarity of acid = 9 × 10⁻³ equivalent, In a 2 g sa...

1) The formulae of the ions of four elements are shown below. O²⁻, F⁻, Li⁺, Mg²⁺ Which statement about these ions is correct? They all have a) The same number of electrons in their outer shells. b) The same electronic structure as a noble gas. c) The same number of protons in their nuclei. d) More e...