Chemistry Forum

5.9 g of trimethyl amine [ (CH₃)₃N ] is added to enough water to make 1.0 L of solution. 50.0 mL of this solution is placed in an Erlenmeyer flask and is then titrated with 0.100 M HCl. a.Calculate the pH of the solution in the Erlenmeyer flask before the titration is started. b.Calculate the pH of ...

Consider the example of dissolution of Na(s) in H2O(l) represented by the following equation:

\(Na(s) + H_2O(l) \rightleftharpoons NaOH(s) + H^+\). Now, In this case, which is conjugate acid and which is conjugate base?

How did you compute the molar ratio of C:H as 4: 10 according to moles of CO2 and H2O? I am not saying the reaction stated in my original thread is correct. I just expressed my opinion. In the original question reaction is not given. You said the stated reaction is wrong. I agree. Chemistry Professo...

A 7.49g sample of compound of C, H, and O burns in presence of oxygen to produce 15.0g CO2 and 8.17g H2O. ? What mass of Oxygen was present in original sample? What is this reaction equation? Answer:- We Know mass of sample of compound = 7.49g, 15.0 g of CO2= 0.3409 M. 8.17g of H2O = 0.4534 M I thin...

Let the initial concentration of H2 is x. Then equation would be \(K_c= \frac{[CH_3OH]}{[CO][H_2]^2}\Rightarrow 25= \frac{[0.2]}{[0]*[x]^2} \Rightarrow 25=\infty\) is practically impossible.

Answers:- CO(g) + 2 H2(g) <=> CH3OH(g) a. When 0.10 mole of CH3OH(Methanol) are obtained, 0.1 mole of CO(g) and 0.2 mole of H2(g) must be consumed. Hence K_c= \frac{CH_3OH}{(CO) (H_2)^2} \Rightarrow \frac{0.10}{(0.1)(0.2)^2}=25 b. If 0.10 mole of CH3OH is added to equilibrium mixture of part a, let ...

Consider the reaction: CO(g) + 2 H2(g) → CH3OH(g) a]When 0.20 mole CO are mixed with 0.40 mole H2 in an empty 1.0 L flask, 0.10 mole of CH3OH are obtained when equilibrium is established. Calculate the equilibrium constant. b]If 0.10 mole of CH3OH are added to the equilibrium mixture of part a, how ...

Okay, Thanks.

Thanks for correction. But can we write this reaction in this way also?
FeBr2 + 4 F2 => FeF2 + 2 BrF3

Reaction in 2.c is \(2F + FeBr_2 \rightarrow FeF_2 + Br_2\)

Saline hydrides are known to react with water violently producing fire. Can CO2, a well known fire extinguisher, be used in this case? Explain I have three answers. Which answer is correct? I think second and third answers are same. Answer1:- Saline hydrides (example: NaH, LiH, etc.) on reaction wit...

What do you think about this answer provided to me in respect of three of these seven compounds? The electrical conductance of a molecule depends upon its ionic or covalent nature. Ionic compounds conduct, whereas covalent compounds do not. BeH2 is a covalent hydride. Hence, it does not conduct. CaH...

Arrange the following in the order of increasing electrical conductance.
O2H2, Hf(II)H2, BeH2, SrH2, CaH2,TiH2,TeH2.

My answer: Electronegativity:- (H)=2.2, Be=1.6, Hf=1.3, O=3.4 Ca, Sr=1,Ti= 1.5

BeH2<TiH2<Hf(II)H2<O2H2=CaH2=SrH2.

Is this answer correct?

Oh, Yes. Thanks.

\( CuSO_4(aq) + Na_2S(aq) \rightarrow Na_2SO_4(aq)+ CuS(aq) \)

\(3AgNO_3(aq) + Na_3PO_4(aq) \rightarrow 3NaNO_3(aq) + Ag_3PO_4(aq)\)