Search found 1563 matches

by ChenBeier
Fri Feb 09, 2024 1:52 pm
Forum: Chemistry forum
Topic: Has anyone tried chloroform?
Replies: 1
Views: 275

Re: Has anyone tried chloroform?

Sorry we dont discuss this kind of things.
by ChenBeier
Fri Feb 09, 2024 7:07 am
Forum: Chemistry forum
Topic: Titration of mixture of KOH and K2CO3
Replies: 11
Views: 1270

Re: Titration of mixture of KOH and K2CO3

First get concentration of HCl

Develop the redoxreaction iodate iodine and the consumed H+.

IO3- + 5 I- + 6 HCl => 3 I2 + 3 H2O + 6 Cl-


With the two first titration you get K2CO3 pH 8.2 and the mixture with KOH pH 4.5 , the difference is KOH

From that calculate mass of K.
by ChenBeier
Mon Feb 05, 2024 11:56 am
Forum: Chemistry forum
Topic: Exercise on pH
Replies: 3
Views: 545

Re: Exercise on pH

Where did you get the ka value from? The value is wrong. Potassium nitrate is a salt made by nitric acid and potassium hydroxide. Both are strong chemicals, acid and base. Also pH should be near neutral. Ka of HNO3 = 20,89, pKa =-1,32 Normaly pH = 14 - 1/2 * (pkB - lg [c anion]) If the value is righ...
by ChenBeier
Fri Feb 02, 2024 3:43 pm
Forum: Chemistry forum
Topic: Electrochemistry
Replies: 3
Views: 1033

Re: Electrochemistry

You are right the concentration is less as 2 M
But its 2 mol/l - 8 *10^(-9) mol/l = 1,999999992 mol/l ~ 2 mol/l
So its near the same.
by ChenBeier
Fri Feb 02, 2024 12:39 pm
Forum: Chemistry forum
Topic: Electrochemistry
Replies: 3
Views: 1033

Re: Electrochemistry

Why do you think the concentration of SO4 2- is wrong. You have 2 M H2SO4 so the value is right.

E =E0 + 0,059V/ z * log c Pb 2+

c Pb 2+ = ksp(PbSO4) / c SO4 2-

cPb 2+ = 1,6 *10^-8 (mol/l)^2 / 2 mol/l = 8 *10^(-9) mol/l

E = -0,126 V+ 0,059/2 * log (8*10^(-9))
E = -0,126V -0,238 V
E = -0,36 V
by ChenBeier
Tue Jan 30, 2024 11:25 pm
Forum: Chemistry forum
Topic: Stoichiometry problem
Replies: 5
Views: 1691

Re: Stoichiometry problem

Why not give yours first?
by ChenBeier
Sun Jan 28, 2024 9:15 am
Forum: Chemistry forum
Topic: Stoichiometry problem
Replies: 5
Views: 1691

Re: Stoichiometry problem

What is your result?
by ChenBeier
Sun Jan 28, 2024 6:12 am
Forum: Chemistry forum
Topic: Stoichiometry problem
Replies: 5
Views: 1691

Re: Stoichiometry problem

The calculation for oxygen is wrong, because the molecule also contain oxygen. The masses of CO2 and H2O correspond to C and H. Calculate the moles of it and do a ratio to unbroken numbers. The mass of silverchloride correspond to the mass of Chlorine. Do also mole ratio. If you have C, H and Cl sub...
by ChenBeier
Fri Jan 26, 2024 12:38 pm
Forum: Chemistry forum
Topic: Funny quizz
Replies: 0
Views: 2118

Funny quizz

by ChenBeier
Fri Jan 26, 2024 3:59 am
Forum: Chemistry forum
Topic: Precipitation reactions
Replies: 4
Views: 3042

Re: Precipitation reactions

The Person who can read has the advantage. Solution see above.
by ChenBeier
Thu Jan 25, 2024 8:51 am
Forum: Chemistry forum
Topic: I need help with finding molar ratio
Replies: 11
Views: 6820

Re: I need help with finding molar ratio

3 Ca(NO3)2 * 4 H2O + P2O5 => Ca3(PO4)2 + 6 HNO3 + H2O

HNO3 decompose to

4 HNO3 => 4 NO2 + 2 H2O + O2
by ChenBeier
Mon Jan 22, 2024 12:21 am
Forum: Chemistry forum
Topic: Can somebody please help me!!
Replies: 1
Views: 1413

Re: Can somebody please help me!!

What is generally a condensation, hydrolysis and Addition in chemistry?
by ChenBeier
Mon Jan 22, 2024 12:11 am
Forum: Chemistry forum
Topic: Aqueous solution in both sulfate ion and chromate ion
Replies: 4
Views: 2968

Re: Aqueous solution in both sulfate ion and chromate ion

As I wrote check the solubility products of both.
With them you can calculate the lead concentration.
by ChenBeier
Wed Jan 17, 2024 2:37 am
Forum: Chemistry forum
Topic: I have a question
Replies: 1
Views: 2383

Re: I have a question

Of course. But Palladiumchloride is a salt. What Palladium source you have.
by ChenBeier
Tue Jan 16, 2024 2:20 am
Forum: Chemistry forum
Topic: Buret Reading/ Titration Data
Replies: 3
Views: 3829

Re: Buret Reading/ Titration Data

That is what I am already said. Why repeating?