Search found 1563 matches
- Fri Feb 09, 2024 1:52 pm
- Forum: Chemistry forum
- Topic: Has anyone tried chloroform?
- Replies: 1
- Views: 275
Re: Has anyone tried chloroform?
Sorry we dont discuss this kind of things.
- Fri Feb 09, 2024 7:07 am
- Forum: Chemistry forum
- Topic: Titration of mixture of KOH and K2CO3
- Replies: 11
- Views: 1270
Re: Titration of mixture of KOH and K2CO3
First get concentration of HCl
Develop the redoxreaction iodate iodine and the consumed H+.
IO3- + 5 I- + 6 HCl => 3 I2 + 3 H2O + 6 Cl-
With the two first titration you get K2CO3 pH 8.2 and the mixture with KOH pH 4.5 , the difference is KOH
From that calculate mass of K.
Develop the redoxreaction iodate iodine and the consumed H+.
IO3- + 5 I- + 6 HCl => 3 I2 + 3 H2O + 6 Cl-
With the two first titration you get K2CO3 pH 8.2 and the mixture with KOH pH 4.5 , the difference is KOH
From that calculate mass of K.
- Mon Feb 05, 2024 11:56 am
- Forum: Chemistry forum
- Topic: Exercise on pH
- Replies: 3
- Views: 545
Re: Exercise on pH
Where did you get the ka value from? The value is wrong. Potassium nitrate is a salt made by nitric acid and potassium hydroxide. Both are strong chemicals, acid and base. Also pH should be near neutral. Ka of HNO3 = 20,89, pKa =-1,32 Normaly pH = 14 - 1/2 * (pkB - lg [c anion]) If the value is righ...
- Fri Feb 02, 2024 3:43 pm
- Forum: Chemistry forum
- Topic: Electrochemistry
- Replies: 3
- Views: 1033
Re: Electrochemistry
You are right the concentration is less as 2 M
But its 2 mol/l - 8 *10^(-9) mol/l = 1,999999992 mol/l ~ 2 mol/l
So its near the same.
But its 2 mol/l - 8 *10^(-9) mol/l = 1,999999992 mol/l ~ 2 mol/l
So its near the same.
- Fri Feb 02, 2024 12:39 pm
- Forum: Chemistry forum
- Topic: Electrochemistry
- Replies: 3
- Views: 1033
Re: Electrochemistry
Why do you think the concentration of SO4 2- is wrong. You have 2 M H2SO4 so the value is right.
E =E0 + 0,059V/ z * log c Pb 2+
c Pb 2+ = ksp(PbSO4) / c SO4 2-
cPb 2+ = 1,6 *10^-8 (mol/l)^2 / 2 mol/l = 8 *10^(-9) mol/l
E = -0,126 V+ 0,059/2 * log (8*10^(-9))
E = -0,126V -0,238 V
E = -0,36 V
E =E0 + 0,059V/ z * log c Pb 2+
c Pb 2+ = ksp(PbSO4) / c SO4 2-
cPb 2+ = 1,6 *10^-8 (mol/l)^2 / 2 mol/l = 8 *10^(-9) mol/l
E = -0,126 V+ 0,059/2 * log (8*10^(-9))
E = -0,126V -0,238 V
E = -0,36 V
- Tue Jan 30, 2024 11:25 pm
- Forum: Chemistry forum
- Topic: Stoichiometry problem
- Replies: 5
- Views: 1691
Re: Stoichiometry problem
Why not give yours first?
- Sun Jan 28, 2024 9:15 am
- Forum: Chemistry forum
- Topic: Stoichiometry problem
- Replies: 5
- Views: 1691
Re: Stoichiometry problem
What is your result?
- Sun Jan 28, 2024 6:12 am
- Forum: Chemistry forum
- Topic: Stoichiometry problem
- Replies: 5
- Views: 1691
Re: Stoichiometry problem
The calculation for oxygen is wrong, because the molecule also contain oxygen. The masses of CO2 and H2O correspond to C and H. Calculate the moles of it and do a ratio to unbroken numbers. The mass of silverchloride correspond to the mass of Chlorine. Do also mole ratio. If you have C, H and Cl sub...
- Fri Jan 26, 2024 12:38 pm
- Forum: Chemistry forum
- Topic: Funny quizz
- Replies: 0
- Views: 2118
- Fri Jan 26, 2024 3:59 am
- Forum: Chemistry forum
- Topic: Precipitation reactions
- Replies: 4
- Views: 3042
Re: Precipitation reactions
The Person who can read has the advantage. Solution see above.
- Thu Jan 25, 2024 8:51 am
- Forum: Chemistry forum
- Topic: I need help with finding molar ratio
- Replies: 11
- Views: 6820
Re: I need help with finding molar ratio
3 Ca(NO3)2 * 4 H2O + P2O5 => Ca3(PO4)2 + 6 HNO3 + H2O
HNO3 decompose to
4 HNO3 => 4 NO2 + 2 H2O + O2
HNO3 decompose to
4 HNO3 => 4 NO2 + 2 H2O + O2
- Mon Jan 22, 2024 12:21 am
- Forum: Chemistry forum
- Topic: Can somebody please help me!!
- Replies: 1
- Views: 1413
Re: Can somebody please help me!!
What is generally a condensation, hydrolysis and Addition in chemistry?
- Mon Jan 22, 2024 12:11 am
- Forum: Chemistry forum
- Topic: Aqueous solution in both sulfate ion and chromate ion
- Replies: 4
- Views: 2968
Re: Aqueous solution in both sulfate ion and chromate ion
As I wrote check the solubility products of both.
With them you can calculate the lead concentration.
With them you can calculate the lead concentration.
- Wed Jan 17, 2024 2:37 am
- Forum: Chemistry forum
- Topic: I have a question
- Replies: 1
- Views: 2383
Re: I have a question
Of course. But Palladiumchloride is a salt. What Palladium source you have.
- Tue Jan 16, 2024 2:20 am
- Forum: Chemistry forum
- Topic: Buret Reading/ Titration Data
- Replies: 3
- Views: 3829
Re: Buret Reading/ Titration Data
That is what I am already said. Why repeating?