Search found 257 matches
- Mon Aug 23, 2021 1:41 am
- Forum: Chemistry forum
- Topic: Question based on Titration and pH computation
- Replies: 9
- Views: 8324
Question based on Titration and pH computation
Dissolve 2.0 g of the unknown monobasic acid sample in 100 ml of water. A 20 ml portion of this solution requires 15 ml of 0.12 M NaOH solution to reach the titrations equivalence point. If the molecular mass of the acid is 122 g/mol, determine the purity (%) of the acid. How to answer this question...
- Fri Aug 13, 2021 10:24 am
- Forum: Chemistry forum
- Topic: Unit conversions (electrical)
- Replies: 1
- Views: 3330
Unit conversions (electrical)
Mobile specifications:
Battery power ratings: 2milli amp hours.
Lithium battery energy content : 3.7 watt hours
Now 3.7 watt hours means 13320 Joules or 3.7 volt amp hours , while 0.002 Amp hours means 1Amp per 7.2 seconds. Now how does we can relate both the specifications?
Battery power ratings: 2milli amp hours.
Lithium battery energy content : 3.7 watt hours
Now 3.7 watt hours means 13320 Joules or 3.7 volt amp hours , while 0.002 Amp hours means 1Amp per 7.2 seconds. Now how does we can relate both the specifications?
- Sun Aug 08, 2021 7:09 am
- Forum: Chemistry forum
- Topic: Enthalpy (thermochemistry question)
- Replies: 1
- Views: 3529
Re: Enthalpy (thermochemistry question)
While answering Q(a), it is stated that average temperature at 1 atm pressure was 56°F(13.3333℃). Now the combustion of one mole of CH4 (methane) releases ∆ H° 890.4 kJ/mol at 25℃(298 K) My question is at 13.33333℃ (286.48333 K)what would be ∆H of combustion of one mole of CH4 at 1atm pressure? My a...
- Sat Aug 07, 2021 9:50 am
- Forum: Chemistry forum
- Topic: Electrochemistry question
- Replies: 5
- Views: 4735
Re: Electrochemistry question
t= n*F/I , n= number of moles of electrons required, F= Faraday constant, I= current in Ampere or Coulombs/second.
t=(0.38935756 Moles* 96485 C)/12.5 C/s = 3005.37 seconds, or 50 minutes approx.
t=(0.38935756 Moles* 96485 C)/12.5 C/s = 3005.37 seconds, or 50 minutes approx.
- Sat Aug 07, 2021 3:58 am
- Forum: Chemistry forum
- Topic: Enthalpy (thermochemistry question)
- Replies: 1
- Views: 3529
Enthalpy (thermochemistry question)
During a recent winter month in Sheboygan, Wisconsin, it was necessary to obtain 3500 kWh of heat provided by a natural gas furnace with 89% efficiency to keep a small house warm (the efficiency of a gas furnace is the percent of the heat produced by combustion that is transferred into the house). a...
- Sat Aug 07, 2021 12:25 am
- Forum: Chemistry forum
- Topic: Electrochemistry question
- Replies: 5
- Views: 4735
Re: Electrochemistry question
The volume of silver that gets electroplated is 0.00000400 m³. The mass of silver that gets electroplated is 0.00000400 m³ × 1.05 × 10⁴ kg m⁻³=0.042 kg. The molar mass of silver= 107.8682 g/mol , so moles of silver 42 g/107.87 g = 0.38935756 mole of silver. Hence, moles of electrons required Ag ⁺ (a...
- Thu Jul 29, 2021 9:44 am
- Forum: Chemistry forum
- Topic: Electrochemistry question
- Replies: 5
- Views: 4735
Electrochemistry question
A metal cup of surface area 200. cm^2 needs to be electroplated with silver to a thickness of 0.200 mm. The density of silver is 1.05 \times 10^4 kg m⁻³.The mass of a silver ion is 1 .79 \times 10⁻²⁵ kg and the charge is the same magnitude as that on an electron. How long does the cup need to be in ...
- Wed Jul 28, 2021 8:29 am
- Forum: Chemistry forum
- Topic: Redox reactions
- Replies: 6
- Views: 5096
Re: Redox reactions
In answer to e) , I used basic medium even though HCl is reactant. You said it is wrong. After using acidic medium, the answer is as follows: RRehij.png The balanced net ionic equations for h), i), j) are as follows: h) Bi_2S_3 + 8HNO_3 \rightleftarrows 2Bi(NO_3)_3 + 2NO + 3S + 4H_2O i) H_3AsO_4 + 4...
- Wed Jul 28, 2021 12:32 am
- Forum: Chemistry forum
- Topic: Redox reactions
- Replies: 6
- Views: 5096
Re: Redox reactions
Answers to d), e), f), g).
- Tue Jul 27, 2021 9:59 pm
- Forum: Chemistry forum
- Topic: Electron-transfer reaction
- Replies: 3
- Views: 3852
Re: Electron-transfer reaction
Answers to 1),2),3) and 4) 1) \frac{1 g}{22.99 g/mol Na} \times \frac {1 mol e^-}{1mol Na} \times \frac{96485.3399 C}{1 mol e^-} \frac{1}{10 min \times 60 s/min}= 7.0 C = 7.0 A current will be required to produce 1 g of Na in 10.0 minutes by the electrolysis of molten NaCL 2) 0.624 mol e^- \times \f...
- Sun Jul 25, 2021 2:02 am
- Forum: Chemistry forum
- Topic: Redox reactions
- Replies: 6
- Views: 5096
Re: Redox reactions
Answers to a), b) , C).
- Sat Jul 24, 2021 5:48 am
- Forum: Chemistry forum
- Topic: Redox reactions
- Replies: 6
- Views: 5096
Redox reactions
How to answer all these following questions?
I am working on these questions. If you know the answers to these questions, you may post them. Why can't i paste the screenshot copied on clipboard here?
I am working on these questions. If you know the answers to these questions, you may post them. Why can't i paste the screenshot copied on clipboard here?
- Fri Jul 23, 2021 9:13 am
- Forum: Chemistry forum
- Topic: Electron-transfer reaction
- Replies: 3
- Views: 3852
Electron-transfer reaction
1)What current will be required to produce 1.0 g of Na in 10.0 min. by electrolysis of molten NaCl? 2) What quantity of electricity will provide 0.624 mol of electrons? 3)If the current is 3.5 A, how many Coulombs per second are passing through the cell? 4) How many minutes will be required for a cu...
- Fri Jul 09, 2021 2:36 am
- Forum: Chemistry forum
- Topic: Drawing chemical structure of C₂₈H₄₀O₇
- Replies: 0
- Views: 29377
Drawing chemical structure of C₂₈H₄₀O₇
How can i draw chemical structure of C28H40O7 Phorbol 12,13- Dibutanoate in ACD/Chemsketch ACD/Labs 2020.1.1 (file version C15E41 Build 115819)
- Mon Jul 05, 2021 9:52 am
- Forum: Chemistry forum
- Topic: Computing mass of CaF₂
- Replies: 3
- Views: 3960
Re: Computing mass of CaF₂
Mass of the CaF2 is 0.0304718 moles × 78.1 g(molar mass of CaF2 = 2.38 g. I computed the solubility of CaF2 Calcium Fluoride in grams per liter in water from the Kₛₚ 3.5e-11 = 1.6 × 10⁻² g CaF2/L. Molar solubility of CaF2 in 0.07145 M of NaF solution is 4.89E-10 M. Are the above answers correct? How...