Search found 1562 matches
- Mon Aug 23, 2021 2:48 am
- Forum: Chemistry forum
- Topic: Flavouring unflavoured Essential Amino Acids / BCAAs
- Replies: 3
- Views: 3791
Re: Flavouring unflavoured Essential Amino Acids / BCAAs
What is the topic, for what you need the Amino acids.
- Mon Aug 23, 2021 2:45 am
- Forum: Chemistry forum
- Topic: 4-Nitrophthalonitrile Supplier
- Replies: 1
- Views: 3121
Re: 4-Nitrophthalonitrile Supplier
No commercials here.
- Mon Aug 23, 2021 2:45 am
- Forum: Chemistry forum
- Topic: Question based on Titration and pH computation
- Replies: 9
- Views: 8133
Re: Question based on Titration and pH computation
Compare the theoretical consumption with the real one.
Calculate the moles you used and the moles of the NaOH react.
Calculate the moles you used and the moles of the NaOH react.
- Sun Aug 22, 2021 3:39 am
- Forum: Chemistry forum
- Topic: Making Potassium Citrate from Citric Acid From Lemons
- Replies: 4
- Views: 4229
Re: Making Potassium Citrate from Citric Acid From Lemons
Carbonate will be destroyed by acid to CO2 and water. So this can be used. Hydroxid get neutralization to water. All others have not effekt.
- Sat Aug 21, 2021 3:24 am
- Forum: Chemistry forum
- Topic: Making Potassium Citrate from Citric Acid From Lemons
- Replies: 4
- Views: 4229
Re: Making Potassium Citrate from Citric Acid From Lemons
Potassium hydrogen carbonate, potassium carbonate and potassium hydroxide can be used.
- Thu Aug 19, 2021 11:22 pm
- Forum: Chemistry forum
- Topic: palladium chloride synthesis?
- Replies: 1
- Views: 3103
Re: palladium chloride synthesis?
Palladium(II) chloride is prepared by dissolving palladium metal in aqua regia or hydrochloric acid in the presence of chlorine. Alternatively, it may be prepared by heating palladium sponge metal with chlorine gas at 500 °C.
- Thu Aug 19, 2021 11:17 pm
- Forum: Chemistry forum
- Topic: Assistance to find value of Constant a and Constant b
- Replies: 2
- Views: 3448
Re: Assistance to find value of Constant a and Constant b
Here we go Propadiene a = 8,23 l^2* bar/ mol^2, b= 0,0747 l/mol Methylacetylene is Propyne a = 8,4 l^2*bar/mol^2, b= 0,0744 l/mol https://www.google.com/url?q=https://drjvazque.files.wordpress.com/2017/08/propiedades-criticas.pdf&sa=U&ved=2ahUKEwjks6Gn-L7yAhXFxoUKHWKhAJQQFnoECAgQAQ&usg=A...
- Mon Aug 16, 2021 8:46 am
- Forum: Chemistry forum
- Topic: calculation of molar fraction and pressure
- Replies: 3
- Views: 3835
Re: calculation of molar fraction and pressure
I am really sorry to hear that a fire is close to your place. This planet is dying.
Your results are correct.
Your results are correct.
- Fri Aug 13, 2021 12:35 pm
- Forum: Chemistry forum
- Topic: What is upstream and downstream in pumps?
- Replies: 1
- Views: 3298
- Fri Aug 13, 2021 12:30 pm
- Forum: Chemistry forum
- Topic: Unit conversions (electrical)
- Replies: 1
- Views: 3314
Re: Unit conversions (electrical)
All nonsense
1 J = Nm =1 Ws = 1 VAs
3,7 Watt is power not not work, the time is missing
13320 J is 13320 VAs = 3,7 VAh
The Charge is 7,2 * 10^-3 Ah, if the voltage is known then the work can be calculated.
1 J = Nm =1 Ws = 1 VAs
3,7 Watt is power not not work, the time is missing
13320 J is 13320 VAs = 3,7 VAh
The Charge is 7,2 * 10^-3 Ah, if the voltage is known then the work can be calculated.
- Thu Aug 12, 2021 8:12 am
- Forum: Chemistry forum
- Topic: calculation of molar fraction and pressure
- Replies: 3
- Views: 3835
Re: calculation of molar fraction and pressure
Consider the vessel is 8 dm^3. In this is filled 2,5 dm^3 CH4 and 4.5 dm^3 O2 . In total 7 dm^3. 1 dm^3 is missing so we have some expansion. of the gases. The two pressures are also different. p1V1 + p2V2 = ptotal* Vvessel pV ~ n. RT is constant. From this you have to get total pressure and the par...
- Wed Aug 11, 2021 12:11 pm
- Forum: Chemistry forum
- Topic: gaseous mixtures
- Replies: 6
- Views: 4599
Re: gaseous mixtures
The candidate has 99 points. If you reach 100 points you get a light cookie.
But to achieve this calculation it goes faster 2,666/5 = 0,5332
And 2,333/5 = 0,4666
Because V~ n.
But to achieve this calculation it goes faster 2,666/5 = 0,5332
And 2,333/5 = 0,4666
Because V~ n.
- Wed Aug 11, 2021 6:28 am
- Forum: Chemistry forum
- Topic: gaseous mixtures
- Replies: 6
- Views: 4599
Re: gaseous mixtures
What is your result?
- Tue Aug 10, 2021 11:42 am
- Forum: Chemistry forum
- Topic: gaseous mixtures
- Replies: 6
- Views: 4599
Re: gaseous mixtures
pV = nRT
P, R and T are constant so n~V
V(CH4) + V(C2H6) = 5 dm^3
2V(O2(CH4)) + 3,5V(O2(C2H6)) = 13,5 dm^2
Substitute Ethane by 5dm^3 - V(CH4) = V(C2H6)
x + y = 5
2 x + 3,5 y =13,5
P, R and T are constant so n~V
V(CH4) + V(C2H6) = 5 dm^3
2V(O2(CH4)) + 3,5V(O2(C2H6)) = 13,5 dm^2
Substitute Ethane by 5dm^3 - V(CH4) = V(C2H6)
x + y = 5
2 x + 3,5 y =13,5
- Sun Aug 08, 2021 8:54 am
- Forum: Chemistry forum
- Topic: Purity of hydrogen obtained via brine electrolysis
- Replies: 1
- Views: 3037
Re: Purity of hydrogen obtained via brine electrolysis
If sulfur compounds Oxidation number lessthen +6 in the brine, then the electrolysis is a Reduction, what can create Hydrogen sulfide.