Chemistry Forum

They use different solubilities, Fraction cristallisation.

Sorry, we don't discuss to make explosives. These are forum rules.

Read here

https://en.m.wikipedia.org/wiki/Bifenthrin

Something else? This is not a homework forum.
What are your ideas what can happen?

I would say Fluorine ethyne acetic acid ester.

Aniline is correct.

A sp 180 °
B sp3 112 °
C sp2 120 °
D sp3 109 °
E sp2 120 °
F sp3 107 °

What a big deal

4 C10H10BrNO3 + 47 O2 => 40 CO2+ 4 HBr+ 4 NO2+ 18 H2O

Sorry it is nonsense what you say. Even Chloroplatinic acid is used as an catalyst it is inorganic and not organic. If you don't know the difference then your expertise is poor.

By the way we dont like comercial Postings.

Convert mM in mg/l, use m = n* M
The density is not necessary, because its a solid material. You can only dissolve a powder in water. No volume.
Then calculate it for 10 ml.

Its ok , but there are no half molecules even mathematicaly correct

Times two

2 C2H6 + 7 O2 => 4 CO2 + 6 H2O

Yes of course it will work. But you have to know which one you will make. Citric acid has 3 Protons, these can be exchanged step by step by a metal, here Calcium, which is bivalent. So there will be CaHCit., Ca(H2Cit)2 and Ca3(Cit)2.

We can not give answers for pharmaceutical purpose.

(Hydroxy)-citric acid can be neutralized with Calcium carbonate to the citrate.

You cannot determine different Isotops of one element by titration. If you check for potassium then you will get all Isotopes together. The Isotopes are different by the amount of neutrons in the atom, this is not possible to figure out by chemical analysis. The chemical behaviour is driven by the a...

In this case convert all to KCl. pH 7.

Probably the determination of molarity of HCl is also wrong. If it was only the half instead 0.0098 M only 0.0049 M then it would more or less fit.

The solution p Value is sum of KOH and 1/2 K2CO3 or KHCO3 ( ml HCl consumed Phenolphthalein) m value is sum of KOH and K2CO3 ( ml HCl consumed Methylorange) n (KOH) = 2 p - m = 2*(KOH + 1/2 K2CO3) - (KOH + K2CO3) = KOH n ( K2CO3) = 2*(m-p) = 2*(KOH + K2CO3 - (KOH + 1/2 K2CO3)) = K2CO3 n KOH = 2 * 26...