Chemistry Forum

Yes, you right,

I solved it again and I used this method:

molality Solute = m(molality) * molar weight * Kg

mste: 3 * 84 * 0.2 ( 200 ml to kilogram) = 50.4

i think, that this is the answer

its about molality, thanks for answer, is a question for my class, but I don't understand, because I resolve it, and tha answer was 252 g, buy I'm not sure

This topic is about molality

How many grams of NaHCO3 are needed to prepare a 2 molar solution with 200 mL of water?

Can someone help me, Thanks.!!!