Chemistry Forum

I also calculated it is coming wrong....But it is published in a research article...how it would be...i am having the same doubt...
What should I do now...Should i mail and ask the author... or if u know any person who may know the solution kindly let me know....I am requesting you to help me.

attaching the links here https://onlinelibrary.wiley.com/doi/full/10.1111/wej.12646 refer materials and methods part... https://www.sciencedirect.com/science/article/pii/S0301479718304134 here refer 2.3 lethal dose analysis Thankyou so much for your responses....Kindly help me if you know the solution

sir...I could not able attach the link here...shall I mail u the highlighted pdf which I have

ok sir...sorry now i understood my mistake....I don't know in that research article they equated it (0.529 g/L as 5% Co2 solution)....don't know how it came...Kindly refer that article I mentioned above Kindly help me in this...is there anything to do with this pH equation. please help me **********...

Hai.... Thankyou so much for your immediate response... As you said.... 1.3 g /106 g/ mol = 0.012 mol Na2CO3 this corresponds multiplied with 44 g/ mol to 0.528 g CO2 . which means 0.528 g of CO2 in 1000ml since per liter is mentioned... is equivalent to 5g in 100ml. But % solution means it always a...

Hi, I have a doubt about making an equivalent %co2 solution with sodium carbonate. I have attached the reference equation quoted in the research article. If anyone knows how to derive the equation kindly help me. How 1.3g/L of Na2CO3 came for 5% Co2 solution and help me to find out for 50% co2. I ha...