Chemistry Forum

ChenBeier wrote: ↑Tue Jun 21, 2022 10:58 am Its only a diluted solution nothing else. You can choose any amount only to achieve Ca/P = 1.5. Maybe its also a matter of soloubility. I would go according the receipe.

Thank you for your help. I will try it out according to the recipe

It is the same equation like above. I wrote the result already. It is only 1/100 of the calculated value. Moles = mass/ Molar mass, n = m/M In case of P4O10 is the result more worse, because 1 mol P4O10 = 4 mol P It is more worse then 1/0.166666 Ca/P4O10 = 1/4*0,16666 Ca/P = 1/0,66666 = 1.5 The mas...

The calculation for P2O5 is wrong its only 47,328 g Molar weight of P2O5 is 142 g/ mol. Multiplied with 0.3333 is 47.3286 g The other answer is 1 mol to 0.333 mol can also diluted down In this case 0.01 mol to 0.0033 mol What means in mass 2,36 g Calcium Nitrate tetra hydrate and 0,473 g Phosphorou...

You need 1 mol of the Calcium nitrate tetra hydrate and 0.333 mol of the phosphorous Penta oxide. One 1 mol Ca(NO3)2*4H2O correspond to 1 mol Ca and 1 mol P2O5 correspond to 2 mol P Ratio Ca/P = 1.5 = 1/0,666 mol = 1 Ca(NO3)2*4H2O /0,333 P2O5 With the molar mass of each component you can calculate ...

I am currently using Ca(NO3)2*4H2O and P2O5 and I need to have the molar ratio of Ca/P = 1.5
I wonder how could I do that?

Thank you for your help