Search found 7 matches

Sat Nov 06, 2021 12:29 pm
Forum: Chemistry forum
Topic: Determining mass for solutions
Replies: 8
Views: 1154

Re: Determining mass for solutions

Molar mass of KCLO3 is 39 + 35.5 + 16(x3) = 122.5 = 122.5g per 1 mole solution Molar mass of KCLO3 for 0.5M solution = 122.5g divided by 2 = 61.25g per .5 mole solution
Sat Nov 06, 2021 12:23 pm
Forum: Chemistry forum
Topic: Chemical equations
Replies: 2
Views: 653

Re: Chemical equations

That's weird. This was the question the lecturer gave.
"Write an equation representing the solubility of sugar in the different solvents (3 marks)"
Sat Nov 06, 2021 12:22 pm
Forum: Chemistry forum
Topic: Determining mass for solutions
Replies: 8
Views: 1154

Re: Determining mass for solutions

wow........guess I overcomplicated it, thank you so much
Sat Nov 06, 2021 12:12 pm
Forum: Chemistry forum
Topic: Determining mass for solutions
Replies: 8
Views: 1154

Re: Determining mass for solutions

yes, so I have to divide the moral mass in half to get the answer for .5 mol? and then add water?? I don't understand completely
Sat Nov 06, 2021 11:54 am
Forum: Chemistry forum
Topic: Determining mass for solutions
Replies: 8
Views: 1154

Re: Determining mass for solutions

Molar mass of KCLO3 is 39 + 35.5 + 16(x3) = 125.5
= 125.5g/ 1 mole
this is what I have so far, what next?
Sat Nov 06, 2021 11:24 am
Forum: Chemistry forum
Topic: Determining mass for solutions
Replies: 8
Views: 1154

Determining mass for solutions

Hi everyone. I have an assignment which requires me to solve this. "Determine the mass of KClO3 required to make a 0.5M solution. Atomic masses: K = 39, Cl =35.5, O = 16" Can someone please tell me what steps I need to go through to get the answer, what do I need to find? I know how to cal...
Sat Nov 06, 2021 11:20 am
Forum: Chemistry forum
Topic: Chemical equations
Replies: 2
Views: 653

Chemical equations

Hi everyone I have an assignment on the solubility of sugar in different liquids. How do I create/ what are chemical equations for
1) sugar + oil
2) sugar + rubbing alcohol
3) sugar + water

Thanks for helping