Chemistry Forum

Oh, of course, the diluted acid will be more... My silly mistake Thanks a lot!

6 300 т --> 100 % acid
x t --> 63 % => 3 969 t 63 % HNO3

correct?

what do you mean - could you please explain the mistake I do? Thanks, N.

1 700 t NH3 / 17 = 100 mole NH3
m(HNO3) = 100 mole * 63 = 6 300 t HNO3

Hi folks, would like to verify the following calculation: How much 63 % HNO3 will the yield be from 1 700 tonnes NH3 (for 24 hours process): НN3 --> A --> B --> HNO3 Synthesis equations (Ostwald process): 4NH3 + 5O2 --> 4NO + 6H2O 2NO + O2 --> N2O4 3N2O4 + 2H2O --> 4HNO3 + 2NO moles NH3:HNO3 = 1:1 n...

ChenBeier wrote: ↑Mon Nov 01, 2021 10:57 am Now it is correct.

Many thanks for confirming!

Yes, many thanks @ChenBeier - meantime I realised my mistake and corrected - it should be for 1) 50 g solution of HCl, and for 2) 42,8 % MgCl2

Greetings,
Ned

Hi people, I'm trying to solve the following problems: Problem 1: 1) How many grams HCl with mass fraction ω=36,5 % will fully dissolve 6 g Mg? 2) What's the mass fraction ω of MgCl2 in the formed solution? For 1) I've calculated that 18,25 g HCl will fully react 6 g Mg - is this correct? For 2) wil...