Search found 35 matches
- Mon Feb 21, 2022 3:02 am
- Forum: Chemistry forum
- Topic: Determine the composition of a gaseous mixture
- Replies: 0
- Views: 28709
Determine the composition of a gaseous mixture
Hi everyone, would you help me understand how to set up the resolution of this exercise: "Calculate the composition of a gaseous mixture of C3H8 and C4H10 and the excess combustion air knowing that the flue gas has the following composition: CO2: 10.76%, H2O: 13.75%, O2: 1.76%, N2: 73.73%."...
- Thu Oct 28, 2021 4:15 am
- Forum: Chemistry forum
- Topic: Determine the equilibrium constant
- Replies: 10
- Views: 4584
- Thu Oct 28, 2021 3:06 am
- Forum: Chemistry forum
- Topic: Determine the equilibrium constant
- Replies: 10
- Views: 4584
Re: Determine the equilibrium constant
I think it's just a minor oversight. You seem to have left your reaction at the "midway" point, because most equations that contain negative coefficients result in some kind of mistake or incorrect answer due to the initial reaction not being properly or fully balanced. The first equation...
- Sun Oct 24, 2021 9:10 am
- Forum: Chemistry forum
- Topic: Determine the equilibrium constant
- Replies: 10
- Views: 4584
Re: Determine the equilibrium constant
Could you please give me another hint? It's an electrochemistry exercise, I've divided the reaction into two half-reactions: R: 2Fe{3+} +2e{-} --> 2Fe{2+} E°= 0,77 V O: H2O2 --> O2 + 2H{+} +2e{-} E°= 0,68 V From here I tried to apply the formula K=10^\frac{nE°_{(fem)}}{0,0592} but I can't get the re...
- Sat Oct 23, 2021 1:26 pm
- Forum: Chemistry forum
- Topic: Determine the equilibrium constant
- Replies: 10
- Views: 4584
Determine the equilibrium constant
Hi everybody, would you help me to understand how to do this exercise:
"Determine the equilibrium constant for the following reaction at 298 K.
2Fe{3+}(aq) + H2O2(aq)--> 2H{+}(aq) + O2(g) + 2Fe{2+}(aq) ."
"Determine the equilibrium constant for the following reaction at 298 K.
- Sat Oct 23, 2021 1:21 pm
- Forum: Chemistry forum
- Topic: calculation of ionisation percentage
- Replies: 4
- Views: 2762
- Sat Oct 23, 2021 7:14 am
- Forum: Chemistry forum
- Topic: calculation of ionisation percentage
- Replies: 4
- Views: 2762
Re: calculation of ionisation percentage
I did so:
pH= -log_10([H+])= 10^-4
%=((10^-4)/(0,6))*100=0,016
but I do not get the expected result (0.02%)
Should I round up?
pH= -log_10([H+])= 10^-4
%=((10^-4)/(0,6))*100=0,016
but I do not get the expected result (0.02%)
Should I round up?
- Sat Oct 23, 2021 2:44 am
- Forum: Chemistry forum
- Topic: calculation of ionisation percentage
- Replies: 4
- Views: 2762
calculation of ionisation percentage
Hi, could you help me with this exercise, please?
"The pH of a 0.6 M solution of a weak acid is 4.0. What is the percentage of ionised acid?"
Thanks.
"The pH of a 0.6 M solution of a weak acid is 4.0. What is the percentage of ionised acid?"
Thanks.
- Thu Sep 30, 2021 9:17 am
- Forum: Chemistry forum
- Topic: Percentage by weight of a mixture
- Replies: 2
- Views: 2080
Re: Percentage by weight of a mixture
thanks, I've already solved it
- Thu Sep 30, 2021 2:53 am
- Forum: Chemistry forum
- Topic: Percentage by weight of a mixture
- Replies: 2
- Views: 2080
Percentage by weight of a mixture
Hi everyone, I have the following exercise: "A solution containing 1.15 g of a mixture of NaOH and KOH is neutralised with 48.4 mL of 0.500 N H2SO4 solution. Calculate the percentages by weight of NaOH and KOH in the original mixture." Would you help me to understand how to solve it? Thank...
- Thu Sep 09, 2021 3:54 am
- Forum: Chemistry forum
- Topic: please, help be with balance
- Replies: 11
- Views: 8905
Re: please, help be with balance
is this the reaction to be balanced?
Na2S2O3 + O3 = SO3 + Na2O2
balanced reaction:
3Na2S2O3 + 5O3 → 6SO3 + 3Na2O2
However, please wait for confirmation from someone more experienced than me.
balanced reaction:
However, please wait for confirmation from someone more experienced than me.
- Wed Sep 08, 2021 5:39 am
- Forum: Chemistry forum
- Topic: chimica inorganica II
- Replies: 10
- Views: 7616
Re: chimica inorganica II
Non c'é di che. Purtroppo non sono in grado di aiutarti, altrimenti avrei risposto anch'io.
- Wed Sep 08, 2021 4:03 am
- Forum: Chemistry forum
- Topic: chimica inorganica II
- Replies: 10
- Views: 7616
Re: chimica inorganica II
La nuova discussione che hai aperto la visualizzo in inglese, forse hai impostato il traduttore automatico sul tuo browser. Per la risposta devi avere un pò di pazienza... appena il moderatore la legge ti risponde
- Wed Sep 08, 2021 3:37 am
- Forum: Chemistry forum
- Topic: chimica inorganica II
- Replies: 10
- Views: 7616
- Wed Sep 08, 2021 3:16 am
- Forum: Chemistry forum
- Topic: chimica inorganica II
- Replies: 10
- Views: 7616
Re: chimica inorganica II
Ciao, ti consiglio di scrivere in inglese, altrimenti difficilmente troverai risposta