Search found 230 matches

by Dhamnekar Winod
Fri May 06, 2022 9:17 pm
Forum: Chemistry forum
Topic: Normality question
Replies: 3
Views: 2096

Re: Normality question

Though, your answer looks to me correct, my doubt is if 173.80 g is equivalent weight, how can we take it as a "Molar mass"? I think in this problem, we should assume (1equivalent acid/1 equivalent base) 20.07 mL x (1 L/1000 mL) x (0.1100 eq base/1 L) x (1 eq acid/1 eq base) x (173.8 g/1 e...
by Dhamnekar Winod
Fri May 06, 2022 4:36 am
Forum: Chemistry forum
Topic: Normality question
Replies: 3
Views: 2096

Normality question

Find the percent acid (eq wt 173.80) if 20.07 mL of 0.1100 N base is required to neutralize 0.721 g of a sample.

What is the answer to this question?
by Dhamnekar Winod
Sat Apr 16, 2022 5:24 am
Forum: Chemistry forum
Topic: Explanation required for 'AmmoniaConcentration' package in 'R'
Replies: 0
Views: 3342

Explanation required for 'AmmoniaConcentration' package in 'R'

Description of 'AmmoniaConcentration' package in 'R'. The total ammonia in aqueous solution is present in two chemical species: un-ionized ammonia, NH3 , and the ionized form, NH4 +. The NH3 species is the one more toxic for aquatic organisms, but current analytical methods do not permit measurement...
by Dhamnekar Winod
Fri Apr 08, 2022 9:21 am
Forum: Chemistry forum
Topic: Chemistry packages in 'R'
Replies: 0
Views: 3291

Chemistry packages in 'R'

What are the benefits of using eChem, chemCal and stoichcalc packages in 'R' ? I downloaded the R Documentations of all of the above mentioned packages. I executed some of the examples of R Documentations, user guides of all of the above mentioned packages. But I didn't understand the answers given ...
by Dhamnekar Winod
Thu Mar 31, 2022 7:41 am
Forum: Chemistry forum
Topic: Equilibrium
Replies: 7
Views: 2374

Re: Equilibrium

Correct answer, thanks.
by Dhamnekar Winod
Wed Mar 30, 2022 6:09 am
Forum: Chemistry forum
Topic: Equilibrium
Replies: 7
Views: 2244

Re: Equilibrium

That's a typographical mistake. I corrected it in my post.
by Dhamnekar Winod
Wed Mar 30, 2022 5:05 am
Forum: Chemistry forum
Topic: Equilibrium
Replies: 7
Views: 2374

Re: Equilibrium

I made appropriate changes in my posts as per your suggestions.

Now in answer to (c), There is an increase of 0.1 mol on SO3. As per chemical reaction 2SO2 + O2 →2 SO3, 50% of 0.10 mol increase in SO3 will be deducted from 0.20 mol of O2 and x is the proportion of an increase of 0.10 mol in SO3.
by Dhamnekar Winod
Wed Mar 30, 2022 4:50 am
Forum: Chemistry forum
Topic: Equilibrium
Replies: 7
Views: 2244

Re: Equilibrium

From ICE table, I found that we have to deduct 0.12 mol from 0.2 mol of F2 and 0.06 mol from 0.10 mol of Xe. That's why my answer matches with author's answer.
by Dhamnekar Winod
Wed Mar 30, 2022 3:59 am
Forum: Chemistry forum
Topic: Equilibrium
Replies: 7
Views: 2244

Re: Equilibrium

But author gave the answer 0.32 mol of F2 which is correct as per my calculations.

As per your calculation x=0.1 mol of F2
by Dhamnekar Winod
Wed Mar 30, 2022 3:49 am
Forum: Chemistry forum
Topic: Equilibrium
Replies: 7
Views: 2374

Re: Equilibrium

My answer to (c) is different than your answer.

My attempt to answer (c) =\(K=\frac{[SO_3]^2}{[SO_2]^2[O_2]}= \frac{ (1.6)^2}{(0.3 + 0.10x)^2(0.2-0.05)} \Rightarrow x=0.695041722823 mol SO_2/L\)
∴ (0.69 mol SO2/L)(10 L)= 6.9 mol of SO2

Is this answer correct? We have to add SO2.
by Dhamnekar Winod
Wed Mar 30, 2022 12:22 am
Forum: Chemistry forum
Topic: Equilibrium
Replies: 7
Views: 2374

Re: Equilibrium

(a)\(K= \frac{[SO_3]^2}{[SO_2]^2[O_2]}\)

(b)\(\frac{(\frac{15 mol}{10 L})}{(\frac{3 mol}{10 L})^2(\frac{2 mol}{10 L})}=125 \)

(c) I am working on this question.
by Dhamnekar Winod
Tue Mar 29, 2022 11:56 pm
Forum: Chemistry forum
Topic: Equilibrium
Replies: 7
Views: 2244

Re: Equilibrium

\((a)K= \frac{[XeF_4]}{[Xe][F_2]^2}= \frac{(0.10)}{(010)(0.20)^2}=25,\)

(b) 80% of 0.20 moles of Xe= 0.80 × 0.20 =0.16 mol XeF4

\(\frac{(0.16)}{(0.040)(0.20 + x -0.12)^2}=25\)

x=0.32 mol F2
by Dhamnekar Winod
Tue Mar 29, 2022 9:15 am
Forum: Chemistry forum
Topic: Equilibrium
Replies: 7
Views: 2244

Equilibrium

Consider the gas-phase reaction Xe + 2F2 ⇌ XeF4 a) Calculate the equilibrium constant from the observation that at some temperature, the extent of reaction is 50% when 0.20 mol of Xe and 0.40 mol of F2 have been mixed in an empty 1.00-L-bulb. b)How many moles of F2 would have to be added to the equi...
by Dhamnekar Winod
Tue Mar 29, 2022 8:23 am
Forum: Chemistry forum
Topic: Equilibrium
Replies: 7
Views: 2374

Equilibrium

The reaction of sulfur dioxide gas with oxygen gas to form sulfur trioxide gas is an important step in the production of sulfuric acid. a) Write the expression for the equilibrium constant. b)If a 10.0 L vessel contains 15 mol of SO3, 2.0 mol of O2, and 3.0 mol of SO2 at equilibrium at 1373 K, what ...
by Dhamnekar Winod
Tue Mar 29, 2022 8:07 am
Forum: Chemistry forum
Topic: Stoichiometry
Replies: 3
Views: 1821

Re: Stoichiometry

a) Percentage composition of the compound:
Carbon:75.41%
Nitrogen:8.36%
Hydrogen:6.62%
Oxygen:9.61%

b) C21H22N2O2
c)C21H22N2O2