Search found 16 matches

by 555gag
Sat Nov 07, 2020 3:43 am
Forum: Chemistry forum
Topic: Chemical kinetics
Replies: 0
Views: 5175

Chemical kinetics

Hello, I could ask to check the kinetic equations, I added the reaction mechanism using a picture. The mechanism was performed in 25 ml of n heptane to which one gram of catalyst was added. dcA/dt=-(k1+k2)*cA dcB/dt=-(k3+k4)*cB dcC/dt=-k5*cC dcD/dt=k1*cA-k6*cD dcE/dt=k2*cA+k3*cB-k7*cE-k8*cE-k9*cE dc...
by 555gag
Thu Nov 05, 2020 3:57 am
Forum: Chemistry forum
Topic: Mercury porosimetry
Replies: 2
Views: 1552

Re: Mercury porosimetry

Thank you.
I done it, but i dont what else
by 555gag
Wed Nov 04, 2020 12:53 pm
Forum: Chemistry forum
Topic: Mercury porosimetry
Replies: 2
Views: 1552

Mercury porosimetry

Hello, i have problem to find dV/dp, when I have this task: Find the distribution function of the pore volume Dv (r) in the sample as a function of the pore radius based on the measurement made on the mercury porosimeter. p -pressure (psia) Volume(cm3) 50 0,085 200 0,142 500 0,251 1000 0,33 5000 0,4...
by 555gag
Tue Apr 28, 2020 11:18 am
Forum: Chemistry forum
Topic: Chemical calculation
Replies: 13
Views: 6295

wrong,
n(Fe2(SO4)3 = n(fe)/2 = Mfe/2*Mfe = 0,107
mFe2(SO4)3 = 0,107*399,88 = 42,78 mg
by 555gag
Tue Apr 28, 2020 11:14 am
Forum: Chemistry forum
Topic: Chemical calculation
Replies: 13
Views: 6295

n=mFe3+/MFe3+ = 12/55,845=0,214 mol
so ,m Fe2(SO4)3 = 0,214*2*399,88=171,85 mg
is theat right
by 555gag
Tue Apr 28, 2020 10:53 am
Forum: Chemistry forum
Topic: Chemical calculation
Replies: 13
Views: 6295

the isrt is x = 85,926 mg
y= 260, 29 mg
Isthat right ?
by 555gag
Tue Apr 28, 2020 10:51 am
Forum: Chemistry forum
Topic: Chemical calculation
Replies: 13
Views: 6295

Please, can you tell me a solution, i still counting, but it still less.
by 555gag
Tue Apr 28, 2020 10:14 am
Forum: Chemistry forum
Topic: Chemical calculation
Replies: 13
Views: 6295

Ok, when i got it right. 12mg............M(Fe3+) = 55,845 g/mol x...................M(Fe2(SO4)3) = 399,88 g/mol x= 0,085mg Fe2(SO4)3 80,7 mg..............M(Ti4+) = 47,867 g/mol y........................M(TiOSO4) = 159,94 g/mol y= 0,29 mg. So, in 100ml H2o i have to dissolve 0,29 mg TiOSO4 ? but, if ...
by 555gag
Tue Apr 28, 2020 9:33 am
Forum: Chemistry forum
Topic: Chemical calculation
Replies: 13
Views: 6295

Ti:Fe = 1:0,125
Fe3+ (wt%) = 12
Ti4+ (wt%)=80,7
SO4 2-(wt%)=7,3
by 555gag
Tue Apr 28, 2020 9:32 am
Forum: Chemistry forum
Topic: Chemical calculation
Replies: 13
Views: 6295

In a typical process, the defined amount of TiOSO4 (table 1) was dissolved in 100 ml of hot distilled water acidified with 10 ml 98% H2SO4. The pelluid liquid was diluted in 4 L of distilled water, a definied amount of iron(III) sulphate hydrate Fe2(SO4)3*xH2O was added and the solution was mixed wi...
by 555gag
Tue Apr 28, 2020 6:53 am
Forum: Chemistry forum
Topic: Chemical calculation
Replies: 13
Views: 6295

Chemical calculation

http://dx.doi.org/10.1016/j.apsusc.2015.02.181 Hello, can i have a question, please. Article above part Experiment, I have problem to calculate amount of TiOSO4 anf Fe2(SO4)3.xH2O. I dont understatnd, how did they mean this in table 1. i started with TiOSO4 w(tioSO4) = m(TiOSO4)/(m(tioso4)+m (h2o) m...
by 555gag
Sat Apr 25, 2020 9:51 am
Forum: Chemistry forum
Topic: Anorganic chemistry
Replies: 5
Views: 4058

The company used this in Czech republic. It´s very interesting, but i dont know, why they used there.
by 555gag
Fri Apr 24, 2020 1:38 pm
Forum: Chemistry forum
Topic: Anorganic chemistry
Replies: 5
Views: 4058

It is used in the chloride mechanism to produce titanium dioxide.
by 555gag
Fri Apr 24, 2020 9:59 am
Forum: Chemistry forum
Topic: Anorganic chemistry
Replies: 5
Views: 4058

Anorganic chemistry

Why boric acid is added to water vapor when removing hcl and cl2?
Thank you so much
by 555gag
Mon Mar 23, 2020 4:06 am
Forum: Chemistry forum
Topic: material balance
Replies: 3
Views: 2646

thank you so much, so now it's right?

Current composition 1
nO2=(nH2/4)*100/85= 14 072 mol

Current composition 3.
nO2 = 14 072 mol
n(inert) = no2*5/85 = 14 072*5/85 = 828 mol