I have found the answers to balancing this equation, but am still unable to figure out how they get the numbers.
KNO3+C12H22O11=N2+CO2+H2O+K2CO3
reactants finish off as 48KNO3+5C12H22O11 and i cannot figure out how we get the 5
Please Help
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- Wed Feb 21, 2018 3:55 pm
- Forum: Chemistry forum
- Topic: Hard to Balance equations
- Replies: 1
- Views: 5442