Chemistry Forum

I can't seem to figure out a reaction for CuSO4*5H2O + (NH4)2S2O8 in the presence of pyridine to make [Cu(py)4]S2O8. Where should the waters go? Should the SO4 join with the ammonium? Same as for AgNO3 and (NH4)2S2O8 in the presence of pyridine to make [Ag(py)4]S2O8. Please, please, pleaaase help me...