## Search found 974 matches

- Tue Nov 30, 2021 5:01 am
- Forum: Chemistry forum
- Topic: Complete the equation of chemical reaction
- Replies:
**3** - Views:
**59**

### Re: Complete the equation of chemical reaction

For this you need only to bake the Acetate. Dont need impurities with carbon compounds.

- Tue Nov 30, 2021 4:52 am
- Forum: Chemistry forum
- Topic: Complete the equation of chemical reaction
- Replies:
**3** - Views:
**59**

### Re: Complete the equation of chemical reaction

Nothing useful. A slight alcaline oil and a salt nothing special will happen.

For what purpose is this mixture.

For what purpose is this mixture.

- Sat Nov 27, 2021 5:30 am
- Forum: Chemistry forum
- Topic: esterification reactions
- Replies:
**2** - Views:
**65**

### Re: esterification reactions

For what purpose, but try it. If surfactant will not decompose.

- Sat Nov 27, 2021 1:07 am
- Forum: Chemistry forum
- Topic: Need help with this.
- Replies:
**1** - Views:
**57**

### Re: Need help with this.

It is to remove excess carbonyl compounds. It react to a Hydroxyalkylsulfonate

RR'CO + HSO3- => HO-RR'CSO3-

RR'CO + HSO3- => HO-RR'CSO3-

- Thu Nov 25, 2021 6:44 am
- Forum: Chemistry forum
- Topic: Difficulty calculating OH with quadratic formula
- Replies:
**26** - Views:
**270**

### Re: Difficulty calculating OH with quadratic formula

The same error. Mix of H+ and OH-.

- Thu Nov 25, 2021 6:43 am
- Forum: Chemistry forum
- Topic: What is the reaction product of ester and ammonia?
- Replies:
**1** - Views:
**39**

### Re: What is the reaction product of ester and ammonia?

Probably an alkaline ester cleavage. Get the alcohol and the amid of the acid.

- Tue Nov 23, 2021 1:33 am
- Forum: Chemistry forum
- Topic: Difficulty calculating OH with quadratic formula
- Replies:
**26** - Views:
**270**

### Re: Difficulty calculating OH with quadratic formula

I read the thread in the excel forum. I think there is already some confusion. They talking about add NaOH and pH get acidic. That is wrong. The mistake is in your sheet you claiming for pH, but it isn't . The 2.32 is the pOH. Also there is a mixup between pka, pkb pH and pOH There are two equations...

- Mon Nov 22, 2021 2:28 pm
- Forum: Chemistry forum
- Topic: Difficulty calculating OH with quadratic formula
- Replies:
**26** - Views:
**270**

### Re: Difficulty calculating OH with quadratic formula

That is all OK, but you use in both cases the same concentration for OH- and for H+ what was 0,00475 mol. In one case you get the right numbers in the other case not. The H+ concentration is different. cOH- of 0,00475 refers to pOH 2,323 or pH 11,676 This alkaline solution contain H+ ions as well. p...

- Mon Nov 22, 2021 10:37 am
- Forum: Chemistry forum
- Topic: Difficulty calculating OH with quadratic formula
- Replies:
**26** - Views:
**270**

### Re: Difficulty calculating OH with quadratic formula

In the box R 14 the - moles has to be used as H+. You used OH-. Probably also the equilibrium of water has to be considered but I didn't checked it.

Also in the box X 3 above the result ist not pH its pOH. So there is some mixed up generally.

Also in the box X 3 above the result ist not pH its pOH. So there is some mixed up generally.

- Mon Nov 22, 2021 10:00 am
- Forum: Chemistry forum
- Topic: Difficulty calculating OH with quadratic formula
- Replies:
**26** - Views:
**270**

### Re: Difficulty calculating OH with quadratic formula

Let say in this way you have a NaOH solution containing 0,19 g = 0,00475 mol NaOH = OH- , in this solution we have also H+ . So if you have kb then use OH- If you use ka then instead H+ has to be used. It's similar pH = - logcH+, but pOH = -logcOH- You can not use the same number 0,00475 for cH+ and...

- Mon Nov 22, 2021 8:50 am
- Forum: Chemistry forum
- Topic: Calculating enthalpy
- Replies:
**1** - Views:
**55**

### Re: Calculating enthalpy

You have 90 g H2 and 90 g O2 correct.

That mean you have 90/2 = 45 mol H2 and 90/32 = 2,81 mol O2

So you can only do the double what means 5,625 mol H2 bring in reaction

You will get the same amount of water, what is x 18 g/ mol = 101,25 g. The rest of 78,75 g = 39,375 mol H2 is not used.

That mean you have 90/2 = 45 mol H2 and 90/32 = 2,81 mol O2

So you can only do the double what means 5,625 mol H2 bring in reaction

You will get the same amount of water, what is x 18 g/ mol = 101,25 g. The rest of 78,75 g = 39,375 mol H2 is not used.

- Mon Nov 22, 2021 8:36 am
- Forum: Chemistry forum
- Topic: Difficulty calculating OH with quadratic formula
- Replies:
**26** - Views:
**270**

### Re: Difficulty calculating OH with quadratic formula

Did you read what I wrote above. If you use kb then c OH- has to be used. If you use ka then c H+. I think that is the key. First figure out what is the right calculation. Excel is only a tool, what will not solve the problem. initial molarity =C -molarity X pKa -.00475 X 0.63095734448019300000 = -2...

- Mon Nov 22, 2021 5:37 am
- Forum: Chemistry forum
- Topic: Difficulty calculating OH with quadratic formula
- Replies:
**26** - Views:
**270**

### Re: Difficulty calculating OH with quadratic formula

pKb = 13,8 pKa = 0,2

c OH- = 0,00475 mol/l , c H+ = 2,11 * 10^-12 mol/l

Calculate with this one

c OH- = 0,00475 mol/l , c H+ = 2,11 * 10^-12 mol/l

Calculate with this one

- Mon Nov 22, 2021 4:52 am
- Forum: Chemistry forum
- Topic: Difficulty calculating OH with quadratic formula
- Replies:
**26** - Views:
**270**

### Re: Difficulty calculating OH with quadratic formula

I think the problem is the 0,0475 moles. This has also converted to H+ isn't it.

- Mon Nov 22, 2021 4:22 am
- Forum: Chemistry forum
- Topic: Difficulty calculating OH with quadratic formula
- Replies:
**26** - Views:
**270**

### Re: Difficulty calculating OH with quadratic formula

Now I understood what you are talking about. But you mixed strong acid/ base with the weak polyprotic once like HSO4-, H3PO4 and its dissociated. Of course here we have to consider all H+ especially dilution is high and also dissociation is high. But for one protic acid like HCl or base NaOH these c...