Chemistry Forum

Sice you're working with solutions which are molar(M) - mole/L you also need the volume of that solution in order to calculate the number of moles in it. Seeing as adding your substances together makes NaCL and H2O you can also calculate how much of each is produced. If you need further explanation ...

Ok lets begin the math: First we se that 1 mole of Zn and 2 moles oh HCl gives us 1 mole oh hydrogen. 1 mole oh hydrogen weights around 2 grams seeing as molar mass oh 1 hydrogen atom is around 1. There for we just devide the mass of reguired hydrogen by the molar mass of 1 mol and we get: 20g/(2g/m...

You would take the first element in the first set with the second element in the second set, i.e. in your example Ba(NO3)2+NH4OH, Ba would go with OH and make up the first element of the reaction, i. e. BaOH. Then you would take the First element in the second set, i.e. NH4 and combine it with the ...

First it seems the equation might be incomplete seeing as the hydrogen atom specified isnt used, secondly i think you ment ho2 to be H2O2 - hydrogen peroxyde, in that case the equation is as follows:

2-H2O2(aq) + MnO4(aq) = MnO2(s) + 2-O2(g) + 2-H2O(l)