Chemistry Forum

GrahamKemp

Cyclohexanol -> Adipic Acid?

Ultimately

3C6H11OH + 8HNO3 = 3 &#40;COOH&#41;&#40;CH2&#41;4COOH + 8NO + 7H2O

, but the process requires several managed substages to acheive a useful yeild.

GrahamKemp

Nope; no production of hydrogen gas.

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&#40;HPO4&#41;&#123;2-&#125;+ H&#123;+&#125; = &#40;H2PO4&#41;&#123;-&#125;

and

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H3PO4= H&#123;+&#125; + &#40;H2PO4&#41;&#123;-&#125;

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CaHPO4 + H3PO4 = Ca&#40;H2PO4&#41;2

GrahamKemp

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CH2

is mean to be...?

GrahamKemp

That's not going to happen. The oxidation of ethanol produces ethanal, not ethene.

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3 CH3H2OH + K2CrO7 + 4 H2SO4 = 3 CH3CHO + K2SO4 + Cr2&#40;SO4&#41;3+ 7 H2O

GrahamKemp

(Ru++) +(NH4+) + (Br2) = (Br-) +Ru(NO2)2 Todo, balance: Ru{2+} + NH4{+} + Br2 = Br{-} + Ru(NO2)2 Remove the spectator ion Ru{2+} and divide into Red/Ox half cells. 2 NH4{+} = 2 NO2{-&a...

GrahamKemp

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NiS + 2 NaCl = ...

does not proceed in aqueous solution because the

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NiS

is insoluble.

Indeed, these are the products of the precipitation reaction:

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 NiCl2&#40;aq&#41; + Na2S&#40;aq&#41; = NiS&#40;s&#41; + 2 NaCl&#40;aq&#41;

GrahamKemp

Boric Acid + Calcium hydroxide = Calcium borate + Water

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2 H3BO3 &#40;aq&#41; + 3 Ca&#40;OH&#41;2 &#40;aq&#41; = Ca3&#40;BO3&#41;2 &#40;s&#41; + 6 H2O &#40;l&#41;

GrahamKemp

C10H10Fe+(CH3CO)2O = C12H12FeO+C14H14FeO2 is FeH2(C5H4)2 + (CH3CO)2O = FeH(C5H4)2(CH3CO) + Fe(C5H4)2(CH3CO)2 Which suggests water is a biproduct. Use aliasing : FeH2X2 + Y2O = FeHX2Y + Fe...

GrahamKemp

I4O9 = I2O6 + I2 + O2 Oh, this is trickery. I2O6 does not exist. I2O5 does. It is O(IO2)2 On the other side of the equation, I4O9 is I(OIO2)3 with one Iodine in oxidation state +3 and the others are in +5 (and covalently bonded to the oxygen). So one of these Iodine ...

GrahamKemp

MnO2 (s) + O2 = MnO4(-2) + 2electrons. And this is balanced dunno about that H cause it is not possible to create a free atom. :roll: Creating electrons should also be avoided. Charges must balance. Balance with ambient water. 2 MnO2 + 2 O2 + H2O = 2 MnO4{2-} + 4 H{+&...

GrahamKemp

Mostly yes. Water of hydration is not involved in the reaction.

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&#40;NH4&#41;2Fe&#40;SO4&#41;2 + 4NaOH = 2 Na2SO4 + 2 NH3 + Fe&#40;OH&#41;2 + 2 H2O

GrahamKemp

Split into half reactions, removing spectator ions and water and its ions. Balance Oxygen using water. Balance Hydrogen using protons. Then balance the charges using electrons. Merge so that electrons cancel. Note: To make alkaline, add sufficient OH{-} on both sides to neutralise ...

GrahamKemp

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&#91;Co&#40;NH3&#41;4Cl2&#93;&#123;+&#125; + Cl&#123;-&#125; + NH3 + 5 H2O = &#91;Co&#40;NH3&#41;.5H2O&#93;&#123;3+&#125; + 3 Cl&#123;-&#125;

GrahamKemp

PCl3 + ClO3{-} = Cl2 + P2O5 + HCl Half : 2 P{3+} = P2O5 || 2 ClO3{-} = Cl2 Bal O: 2 P{3+} + 5 H2O = P2O5 || 2 ClO3{-} = Cl2 + 6 H2O Bal H: 2 P{3+} + 5 H2O = P2O5 + 10 H{+} |...

GrahamKemp

AgNO3 + NH4OH + CH3CHO = Ag + NH4NO3 + CH3COONH4 + H2O Notice that NH4{+}, NO3{-} are spectators, and the -C=OCH3 functional group remains intact. We can remove the spectators and alias the functional group, then balance the remainder. Do away with the distractio...

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