Chemistry Forum

Hello everyone, i am new in this community and i am seeking help for my thesis. I am stuck in a reaction that i am unable to complete on my own. I have been working on TiO₂ nano-particles doped with silver and manganese. So i used titanium isopropoxide as precursor solution and organic extract is used as reducing agent. so basically the components that i used for my reaction are titanium isopropoxide, silver nitrate(5% mol), sodium hydroxide and for another sample i used titanium isopropoxide, manganese sulphate(5% mol),sodium hydroxide. so can anyone help me to complete this reaction please.

That is only a hydrolysis.

Ti(OC₃H₇)₄ + 2 H₂O => TiO₂ + 4 C₃H₇OH

The Hydroxide will give Manganese- or silver oxide, what will be built in the Titaniumdioxide particles

2 AgNO₃ + 2 NaOH => Ag₂O + 2 NaNO₃ + H₂O

MnSO₄ + 2 NaOH => MnO + Na₂SO₄ + H₂O

A reducer is able to reduce to silver.

Thank you very much for your response. But my product of the reaction must be TiO₂. and when i dope silver it will be AgTiO₂
and for manganese it will be MnTiO₂. Furthermore if the dope percentage of Ag and Mn is x and y respectively then the products will be AgxTi(1-x)O₂ and MnyTi(1-y)O₂. So can you help me in this way?

AgTiO₂ and MnTiO₂ cannot be. Silver is monovalent, manganese bivalent and titanium tetra valent.

The 3 reactions I had given already.

AgxTi(1-x)O₂ and MnyTi(1-y)O₂. Make also no sense
.
If you put 1 for x or y then it would give AgO₂ and MnO₂
Manganese would be possible, but then has to use Mn-IV compound or a oxidiser.

But silver exist only as Ag₂O

I Would say it is x Ag₂O * (1-x)TiO₂ and y MnO* (1-y)TiO₂

2x AgNO₃ + 2x NaOH + (1-×) Ti(OC₃H₇)₄ + (2-x) H₂O => 4*(1-x) C₃H₇OH + xAg₂O(1-x)TiO₂ + 2x NaNO₃

y MnSO₄ + 2y NaOH + (1-y) Ti(OC₃H₇)₄ +(2-y) H₂O=> y MnO(1-y)TiO₂ + y Na₂SO₄ + 4*(1-y) C₃H₇OH

Thank you very much sir. You,ve helped me a lot. I am grateful to this platform as well