How many CO2moles are needed to react completely with 7.2 moles of C6H14?
2 C6H14(g) + 19 O2(g) - > 12 CO2(g) + 14 H2O(g)
I had 620.43g C6H14 X 1 mol C6H14/86.17 g C6H14 X 12 mole CO2/2 mol C6H14 X 44.01g CO2/ 1mole CO2
Answer in book is 68 moles? Not my answeer. How am I setting this up wrong??
Chenmitry
Moderators: Xen, expert, ChenBeier
Are you sure you are asked about CO2 moles. not about O2 moles?
Anyway, given the starting quantity 7.2 moles of C6H14 is 3.6 times bigger than original 2 moles in the equation, you need 3.6 times of the original number of O2 moles:
3.6 x 19 moles = 68.4 moles of O2
Or, if the question "how many moles of CO2 will be produced from 7.2 moles of C6H14?", then:
3.6x12 (original number of moles in the equation)=43.2
Anyway, given the starting quantity 7.2 moles of C6H14 is 3.6 times bigger than original 2 moles in the equation, you need 3.6 times of the original number of O2 moles:
3.6 x 19 moles = 68.4 moles of O2
Or, if the question "how many moles of CO2 will be produced from 7.2 moles of C6H14?", then:
3.6x12 (original number of moles in the equation)=43.2