Redox (base): MnO2 (s) + O2 -> MnO4^(-2) + H

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Elektrische
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Redox (base): MnO2 (s) + O2 -> MnO4^(-2) + H

Post by Elektrische »

Hello everyone! I've already tried to solve this equation, but I just can't. Thanks for the help
Chemikas
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Post by Chemikas »

MnO2 (s) + O2 = MnO4(-2) + 2electrons. And this is balanced dunno about that H cause it is not possible to create a free atom.
GrahamKemp
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Post by GrahamKemp »

Chemikas wrote:MnO2 (s) + O2 = MnO4(-2) + 2electrons. And this is balanced dunno about that H cause it is not possible to create a free atom.
:roll: Creating electrons should also be avoided. Charges must balance.

Balance with ambient water.

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2 MnO2 + 2 O2 + H2O = 2 MnO4{2-} + 4 H{+} 
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