Redox equations....HELP!!!

[mmcglothlin423]

Can anyone please help with these problems??

Use 1/2 reaction method to balance...write each 1/2 reaction and indicate substances being oxidized and reduced. (more than 2 substances undergoing electron change).

Fe(CN)₆^-4 + Ce⁺⁴ ---->Ce(OH)₃ + Fe(OH)₃ + CO₃^-2 + NO₃^-1
in base



Cr(NCS)₆^-4 + Ce⁺⁴ ---->Cr⁺³ + Ce⁺³ + NO₃^-1 + CO₂ + SO₄^-2 in acid

Please HELP!!

[dedanh]

Can anyone please help with these problems??

Use 1/2 reaction method to balance...write each 1/2 reaction and indicate substances being oxidized and reduced. (more than 2 substances undergoing electron change).

Fe(CN)₆^-4 + Ce⁺⁴ ---->Ce(OH)₃ + Fe(OH)₃ + CO₃^-2 + NO₃^-1
in base

Cr(NCS)₆^-4 + Ce⁺⁴ ---->Cr⁺³ + Ce⁺³ + NO₃^-1 + CO₂ + SO₄^-2 in acid

Please HELP!!

i don't understand why there is

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CO3{-} and NO3{-}

, i think it still make

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CN{-}

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Fe(CN)6{-4} + Ce{+4} + 6OH{-} = Ce(OH)3 + Fe(OH)3 + 6CN{-}

that's :
_ oxidation :

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Fe(CN)6{-4} = Fe(OH)3 or Fe{+2} = Fe{+3} + e 

_ reduction :

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Ce{+4} + e = Ce{+3} 

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Cr(NCS)6{-4} + Ce{+4} + 6H{+} = Cr{+3} + Ce{+3} + 6HSCN

that's :
_ oxidation :

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Cr{+2} = Cr{+3} + e

_ reduction :

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Ce{+4} + e = Ce{+3}

that' s my opinion