Chemistry Forum

Molar concentrarion is "moles per Litre". You just need to take the final volume of solution into account. New concentration is the product of old concentration and the ratio of old and new volumes. That's: M 2 = M 1 *V 1 /V 2 75.0mL of a 0.0010M aqueous solution of Fe(NO3)2 into 175.0 mL ...

That is a fairly good explanation. It's quite understandable, and also correct. (1) Divide each elements measured mass by its atomic mass to get the stoichiometric ratio, then (2) Multiply the results by the common factor needed to produce a ratio of lowest possible integers. The result is As 2 O 3 ...

What are the equations showing commercial methods of preparations of the halogen (F2, Cl2, Br2, I2) Chlorine : NaCl + H2O → NaOH + H2↑ + Cl2↑ Bromine : 2 Br– + Cl2↑ → Br2↑ + 2 Cl– Flourine : HF + KF → KHF2 2 HF2– → H2↑ + F2↑ + 2 F– Iodine : 2 HI + Cl2 → I2↑ + 2 HCl I...

NaomiPheonix wrote:I tried using the online balancer from this site and i worked for every equation except:
H2SO3 + Na --->

Quirky. It helps if you provide the expected products (hydrogen and sodium sulfite).

H2SO3 + 2 Na = H2 + Na2SO3

Liam wrote:How many formula units of BeCl2 does 9.15x10^2g of BeCl2 represent?

Beryllium chloride has a molar mass of 79.9182 g/mol.

Therefore: 915 grams contains 11.4 moles.

Charge and oxygen counts just won't balance as it is. It's mathematically impassable. :!: In an aqueous solution, add water and hydrogen ion to the equation. Enterring: MnO4{-} + SO3{2-} + H{+} = MnO2 + SO4{2-} + H2O Balances out to: 2 MnO4{-} + 3 SO3{2-} + 2H{+} = 2 MnO2 + 3 SO4{2-} + H2O --- More ...