C2O4(2-) + MnO4(-) => CO2 + Mn(2+)
5(C2O4(2-) => 2 CO2 + 2e-)
2(8 H(+) + MnO4(-) + 5e- => Mn(2+) + 4 H2O)
Yep, looks like you nailed it.
Search found 77 matches
- Tue Jun 10, 2008 9:47 am
- Forum: Chemistry forum
- Topic: Help Plisssss
- Replies: 1
- Views: 2179
- Sun Jun 08, 2008 4:30 pm
- Forum: Chemistry forum
- Topic: Help with balancing equ.
- Replies: 4
- Views: 4250
- Sun Jun 08, 2008 3:09 pm
- Forum: Chemistry forum
- Topic: Help with balancing equ.
- Replies: 4
- Views: 4250
This is an acid base reaction. Since HF is a stronger acid than HCO3(-), it will give it a proton. You're on the right track. NaHCO3 + HF => H2CO3 + NaF After the carbonic acid forms, it will quickly decompose to water and carbon dioxide. (As instanced by the bubbling from solution). H2CO3 => CO2 + ...
- Sun Jun 08, 2008 3:06 pm
- Forum: Chemistry forum
- Topic: practicing places
- Replies: 1
- Views: 2309
- Sat Jun 07, 2008 3:58 pm
- Forum: Chemistry forum
- Topic: help with equations
- Replies: 3
- Views: 4003
There is no direct way to calculate the power of a reaction, only its energy. This will be tabulated from a reference according to Hess' Law. This is probably quite a bit ahead of stoichiometry, however. Here is an example : 0.90 grams of Aluminum and 2.10 grams of potassium perchlorate are mixed ca...
- Fri Jun 06, 2008 11:15 pm
- Forum: Chemistry forum
- Topic: help with equations
- Replies: 3
- Views: 4003
The dangerous part of mixing bleach and ammonia is formation of chloramines. NH2Cl, NHCl2 and NCl3 are all poisons. None of the products of the 'final' equation are dangerous at all : 4NH3 + 3NaOCl --> 2NaOH + NaCl + H2O + 2NH4Cl + N2 I'm not familiar with NaONH3; it must be some sort of intermediat...
- Fri Jun 06, 2008 11:08 pm
- Forum: Chemistry forum
- Topic: help with understanding what balancing means
- Replies: 3
- Views: 3705
Ah! Well you can figure this out using the molar mass. The molar mass of something is the sum of the atomic weights of its parts. Use your periodic table to guide you. In your example, you would look up Ca to find that it has a molar mass of 40.1 grams per mole. Cl is 35.5 grams per mole, but it com...
- Fri Jun 06, 2008 10:59 pm
- Forum: Chemistry forum
- Topic: pH
- Replies: 3
- Views: 3487
- Thu Jun 05, 2008 8:38 am
- Forum: Chemistry forum
- Topic: What do you get when you have urea + ethanoic acid?
- Replies: 2
- Views: 12239
- Thu Jun 05, 2008 8:18 am
- Forum: Chemistry forum
- Topic: LiClO + NaHSO4 = ??????
- Replies: 1
- Views: 2479
4 NaHSO4 + 5 LiClO => 2 Cl2 + LiClO3 + 2 Na2SO4 + 2 H2O + 2 Li2SO4 Something like that. The exact reaction depends on the temperature, amount of bisulfate added and concentration of the reactants. Sometimes, chlorine oxides will bubble out of the solution. The only thing that is for sure is the for...
- Wed Jun 04, 2008 9:42 am
- Forum: Chemistry forum
- Topic: pH
- Replies: 3
- Views: 3487
- Tue Jun 03, 2008 7:39 pm
- Forum: Chemistry forum
- Topic: Calculating dilution ratio of sulfuric acid and water
- Replies: 10
- Views: 28107
Note : This means 55 ml of sulfuric acid for 1 liter of water. Another note : the sulfuric acid, after this dilution, is going to be approximately 9% concentrated. Final note : The error of this calculation is likely on the side of caution, this amount of water assumes complete dissociation of 98% s...
- Tue Jun 03, 2008 7:36 pm
- Forum: Chemistry forum
- Topic: ethanol
- Replies: 1
- Views: 2405
Conversion problem. Convert to mL, multiply by density, divide by molar mass and multiply the Avagadro's number. 1.25 oz * 29.6 mL / oz = 37.0 mL 37.0 mL * 0.798 g / mL = 29.526 g Molar mass = 46.06844 g / mol 29.526 g / 46.06844 g / mol = 0.6409 moles Avagadro's number = 6.02 * 10^23 0.6409 moles *...
- Tue Jun 03, 2008 7:32 pm
- Forum: Chemistry forum
- Topic: chemical family
- Replies: 1
- Views: 2329
- Tue Jun 03, 2008 7:30 pm
- Forum: Chemistry forum
- Topic: Calculating dilution ratio of sulfuric acid and water
- Replies: 10
- Views: 28107
H2SO4 => HSO4(-) + H(+) From the CRC Handbook of Chemistry and Physics, the dH of this reaction is, according to Hess' Law, -95.34 kJ / mol. Since we can assume any value of moles as long as we keep it consistent, let's do one mole of sulfuric acid and convert this to milliliters later. -95,340 J is...